js-获取树结构的长度
2021-06-10 本文已影响0人
汀上
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
</body>
<script>
let a =[{
"code": "202",
"name": "销售组",
"id": 8959,
"type": 1,
"personNumer": 2,
"parentId": 0,
"selected": null,
"subUserGroupList": [{
"code": "202000",
"name": "一级部门2",
"id": 9086,
"type": 1,
"personNumer": 0,
"parentId": 8959,
"selected": null,
"subUserGroupList": [],
"customerUserGroupContentDTOS": null
}, {
"code": "202001",
"name": "一级部门",
"id": 9087,
"type": 1,
"personNumer": 0,
"parentId": 8959,
"selected": null,
"subUserGroupList": [{
"code": "202001000",
"name": "一级部门1",
"id": 9088,
"type": 1,
"personNumer": 0,
"parentId": 9087,
"selected": null,
"subUserGroupList": [],
"customerUserGroupContentDTOS": null
}],
"customerUserGroupContentDTOS": null
}]
}];
function getListlength(arr, type) {
let num = 0;
function getlength(arr, type) {
num += arr.length;
arr.forEach((ele, i) => {
let next = arr[i][type];
if (next.length > 0) {
num += next.length;
next.forEach((ele, j) => {
getlength(next[j][type], type, num)
})
}
});
}
getlength(arr, 'subUserGroupList')
return num
}
console.log(getListlength(a, 'subUserGroupList')) ; //4
</script>
</html>
