python第三方模块

你应该知道的Python新方法(二)

2018-07-07  本文已影响124人  JM68
from collections import namedtuple

Name = namedtuple('Name', 'name age sex')

a = Name('王大锤', 18, '女')
b = Name('丑小鸭', 20, '鸭')

print(a.name, a.age, a.sex)  # 结果: 王大锤 18 女

print(b.name, b.age, b.sex)  # 结果: 丑小鸭 20 鸭 


name = '王大锤'
sex = '男'
age = 18

print(f'{name}居然只有{age},{sex}?')  # 结果王大锤居然只有18,男?

my_dict = {'e': 4, 'b': 2, 'c': 1, 'd': 3}

a = sorted(my_dict)
b = sorted(my_dict.items())
c = sorted(my_dict.items(), key=lambda x: x[1])

print(a)
print(b)
print(c)

'''
结果:
['b', 'c', 'd', 'e']
[('b', 2), ('c', 1), ('d', 3), ('e', 4)]
[('c', 1), ('b', 2), ('d', 3), ('e', 4)]
'''

x, y, z = 0, 1, 0

if x == 1 or y == 1 or z == 1:
    print('yes')


if x or y or z:
    print('yes')

if 1 in (x, y, z):
    print('yes')

if not all([x, y, z]):
    print('yes')

if any((x, y, z)):
    print('yes')

if all((x, y, z)):
    print('yes')
else:
    print('no')

if x and y and z:
    print('yes')
else:
    print('no')
'''
结果:
yes
yes
yes
yes
yes
no
no
'''

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