dede用ajax提交表单

<div class="container">
  <div class="row">
    <div class="col-xs-8 col-md-8 col-lg-8 col-xs-offset-2 col-md-offset-2 col-lg-offset-2">
      <form class="form-inline" id="form">
        <div class="form-group">
          <label for="name">Name</label>
            <input type="text" class="form-control" id="nameasd" placeholder="Jane Doe" name="nameasd">
        </div>
        <button id="btn" type="button" class="btn btn-default" onclick="add_ajaxmessage()">提交</button>
      </form>
    </div>
   </div>
</div>

<script type="text/javascript">
  function add_ajaxmessage(){
    var dataString = 
    'nameasd='+nameasd.value+ //这个值根据后台定义表单所设置的值
     //'&yx='+yx.value+ //表单的name和id值必须一致，多个input请自行复制此行代码
    '&action=post'+
    '&diyid=1&do=2&dede_fields=nameasd,text&dede_fieldshash=bd9011ed660d9773441aa6c648a42f3f'; 
    //这里的所有值都是根据自定义的值来修改
    $.ajax({
      type: "POST",
      url: "/plus/diy.php",//提交到后台文件
      data: dataString,//传值
      success: function(data) {
        //console.log(data)
        $("#result").text(data);//以html的形式显示在指定id的元素里
        $('#form')[0].reset();//提交后清除id="form"的值
      }
    });
    return false;
  }
</script>