构造奇数阶幻方

2018-08-25  本文已影响0人  burglar

使用的是De la Loubère方法(也叫Siamese method)

#!/usr/bin/env python3
def magic_square(n):
    '''De la Loubere's solution for n-odd magic square'''
    square=[([0]*n) for i in range(n)]
    mid=n//2
    square[0][mid]=1
    count=1
    i=n-1 # i-th row
    j=mid+1   # j-th column
    while count<n*n:
        count+=1
        square[i][j]=count
        i=(i-1)%n
        j=(j+1)%n
        if square[i][j]!=0:
            i=(i+2)%n
            j=(j-1)%n
    return square
if __name__=='__main__':
    n=int(input('input an odd integer:\n'))
    square=magic_square(n)
    for i in range(n):
        print(square[i])
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