R语言:循环
2016-07-24 本文已影响272人
Bioconductor
这里介绍五种R语言的循环语法,分别是:
-
for
-
if
-
repeat
-
which
-
while
for
samples<- c(rep(1:10))
samples
## [1] 1 2 3 4 5 6 7 8 9 10
for(thissample in samples){
print(thissample)
}
## [1] 1
## [1] 2
## [1] 3
## [1] 4
## [1] 5
## [1] 6
## [1] 7
## [1] 8
## [1] 9
## [1] 10
for ( thissample in samples){
str <- paste(thissample,"is current sample",sep = " ")
print (str)
}
## [1] "1 is current sample"
## [1] "2 is current sample"
## [1] "3 is current sample"
## [1] "4 is current sample"
## [1] "5 is current sample"
## [1] "6 is current sample"
## [1] "7 is current sample"
## [1] "8 is current sample"
## [1] "9 is current sample"
## [1] "10 is current sample"
for( thissample in samples){
if (thissample == 3)
break
str<-paste(thissample,"is current sample" , sep = " ")
print (str)
}
## [1] "1 is current sample"
## [1] "2 is current sample"
for(thissample in samples){
if (thissample %% 2 == 0)
next
str<-paste(thissample,"is current sample",sep = " ")
print(str)
}
## [1] "1 is current sample"
## [1] "3 is current sample"
## [1] "5 is current sample"
## [1] "7 is current sample"
## [1] "9 is current sample"
end<-length(samples)
begin <- end -2
for(thissample in begin:end){
str<-paste(thissample,"is current sample",sep = " ")
print(str)
}
## [1] "8 is current sample"
## [1] "9 is current sample"
## [1] "10 is current sample"
if
samples<-c(rep(1:10))
samples
## [1] 1 2 3 4 5 6 7 8 9 10
for(thissample in samples){
if (thissample %% 2 != 0)
next
else
print(thissample)
}
## [1] 2
## [1] 4
## [1] 6
## [1] 8
## [1] 10
ret<-ifelse(samples>6,2,1)
ret
## [1] 1 1 1 1 1 1 2 2 2 2
repeat
total<-0
repeat{
total<-total +1;
print(total);
if (total > 6)
break;
}
## [1] 1
## [1] 2
## [1] 3
## [1] 4
## [1] 5
## [1] 6
## [1] 7
total
## [1] 7
which
which(letters == "h")
## [1] 8
data(BOD)
BOD
## Time demand
## 1 1 8.3
## 2 2 10.3
## 3 3 19.0
## 4 4 16.0
## 5 5 15.6
## 6 7 19.8
which(BOD$demand == 16)
## [1] 4
x<-matrix(1:9,3,3)
x
## [,1] [,2] [,3]
## [1,] 1 4 7
## [2,] 2 5 8
## [3,] 3 6 9
which(x %% 3 == 0,arr.ind = TRUE) #返回位置
## row col
## [1,] 3 1
## [2,] 3 2
## [3,] 3 3
which(x %% 3 == 0,arr.ind = FALSE) # 返回数
## [1] 3 6 9
while
x<-1
while(x<5){
x<-x+1
print(x)
}
## [1] 2
## [1] 3
## [1] 4
## [1] 5
x<-1
while(x<5){
x<-x+1
if(x == 3)
break
print(x)
}
## [1] 2
x<-1
while(x<5){
x<-x+1
if(x == 3)
next
print (x)
}
## [1] 2
## [1] 4
## [1] 5