JAVA8-时间测试,示例
2019-12-04 本文已影响0人
AlanSun2
package com.alan344.time;
import java.time.*;
import java.time.temporal.ChronoField;
import java.time.temporal.ChronoUnit;
import java.time.temporal.TemporalAdjusters;
/**
* @author AlanSun
* @date 2019/12/4 16:11
*/
public class TestTime {
public static void main(String[] args) {
System.out.println(MonthDay.now());
System.out.println(LocalDate.now());
System.out.println(System.currentTimeMillis());
System.out.println(Instant.now().toEpochMilli());
System.out.println(Instant.now().atOffset(ZoneOffset.ofHours(8)));
System.out.println(LocalDateTime.ofInstant(Instant.now(), ZoneId.systemDefault()));
System.out.println("---------------------------------------Duration-----------------------------------");
// 间隔 Duration
LocalDateTime ldt1 = LocalDateTime.of(LocalDate.now(), LocalTime.of(12, 20));
LocalDateTime ldt2 = LocalDateTime.of(LocalDate.of(2018, 11, 4), LocalTime.of(12, 20, 20));
Duration between = Duration.between(ldt1, ldt2);
System.out.println(between.getSeconds());
System.out.println(between.isZero());
System.out.println(between.minus(Duration.ofSeconds(30)).getSeconds());
System.out.println(between.minus(Duration.of(30, ChronoUnit.SECONDS)));
System.out.println("toDays:" + between.toDays()); //换算成天,不足一天,则为0
System.out.println("toHours:" + between.toHours());// 换算成小时,不足一小时,则为0
System.out.println("negated:" + between.negated());// 取反
// Period
System.out.println("---------------------------------------period-----------------------------------");
Period between1 = Period.between(ldt1.toLocalDate(), ldt2.toLocalDate());
System.out.println(between1.getYears());//获取相差的年
System.out.println(between1.getMonths());//获取相差的月
System.out.println(between1.getDays());//获取相差的天
System.out.println(between1.isNegative());// 是否是负数,一般按时间轴计算就是正的
System.out.println(between1.negated()); // 年月日取反
System.out.println("addTo:" + between1.negated().addTo(ldt1));
System.out.println(between1.toTotalMonths());// 把年转化为月,计算总共差几个月
System.out.println(between1.withDays(3));// 把原来的天替换掉
System.out.println(between1);
// 年月标准化:只有第三个是起作用的,因为它只对年月有效
System.out.println(Period.ofDays(410).normalized().getDays());
System.out.println(Period.ofWeeks(60).normalized().getMonths());
System.out.println(Period.ofMonths(40).normalized().getMonths());
System.out.println("------------------------------------------------zone---------------------");
ZonedDateTime now = ZonedDateTime.now();
System.out.println(now);
System.out.println(now.getZone());
System.out.println(now.getOffset());
System.out.println(now.withMonth(11));
System.out.println(now.with(ChronoField.MONTH_OF_YEAR, 9));
System.out.println(now.with(MonthDay.of(3, 2)));
System.out.println(now.with(TemporalAdjusters.dayOfWeekInMonth(2, DayOfWeek.MONDAY)));// 把年月日替换为当月第2周的星期一
System.out.println(now.with(TemporalAdjusters.previous(DayOfWeek.MONDAY)));// 把年月日替换为这一周的周一
System.out.println(now.with(TemporalAdjusters.next(DayOfWeek.MONDAY)));// 把年月日替换为下一周的周一
System.out.println(now.with(TemporalAdjusters.ofDateAdjuster(localDate -> localDate.minusWeeks(1).with(ChronoField.DAY_OF_WEEK, DayOfWeek.SUNDAY.getValue()))));// 把年月日替换为上一周的周一
System.out.println(now.minusWeeks(0).with(ChronoField.DAY_OF_WEEK, DayOfWeek.SUNDAY.getValue()));// 把年月日替换为上一周的周一
}
}
Conclusion
- with 方法主要用于时间的替换。
- Period Duration 都是计算间隔,方法上也相识。Duration 更加通用一点,它能对时分秒进行计算;period 则只能对日期计算,它的好处是能计算相差多少个月。