145. Binary Tree Postorder Trave
2020-08-29 本文已影响0人
jluemmmm
递归实现
- Runtime: 72 ms, faster than 77.14%
- Memory Usage: 37 MB, less than 17.86%
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var postorderTraversal = function(root) {
if(!root) return []
let res = []
let recursive = function(node) {
if(node.left) recursive(node.left)
if(node.right) recursive(node.right)
res.push(node.val)
}
recursive(root)
return res
};
更快的递归实现
- Runtime: 68 ms, faster than 91.12%
- Memory Usage: 36.9 MB, less than 20.19%
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var postorderTraversal = function(root) {
let res = []
recursive(root, res)
return res
};
let recursive = function(node, res) {
if(node) {
if(node.left) recursive(node.left, res)
if(node.right) recursive(node.right, res)
node && res.push(node.val)
}
return
}
非递归实现
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var postorderTraversal = function(root) {
if(!root) return []
let stack = [root]
let res = []
while(stack.length > 0) {
let { val, left, right } = stack.pop()
res.unshift(val)
left && stack.push(left)
right && stack.push(right)
}
return res
};