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顺时针打印矩阵

2016-03-24  本文已影响118人  AwesomeAshe
顺时针打印矩阵

我的想法就是先定下四个角的坐标,然后按行和列打印

这里很重要的是,如果你想用x,y来代表坐标,一点不要把数组的规律和坐标系搞混淆了,这样可能你打印出来是反的.
这里我是这样做的:
数组的下标是:

a00 a01 a02...
a10 a11 a12..
a20 a21 a22...

所以我使用x代表第一个下标,y代表第二个下标
a[x][y]

形象的:

二维数组

大家可以根据这个图:

这是驱动函数:

//judge if input legall!!!
void print_left_right(int a[][100], int start, int end,int y);//x goes up
void print_right_left(int a[][100], int start, int end,int y);//x goes down
void print_up_down(int a[][100], int start, int end,int x);
void print_down_up(int a[][100], int start, int end,int x);
//print an matrix by circle
//the matrix is m*n
void print_matrix(int a[][100], int m, int n)
{
    int startX, startY,endX,endY;
    startX = 0;
    startY = 0;
    endX = m - 1;
    endY = n - 1;
    while (startX < endX && startY<endY)
    {
        print_left_right(a, startY, endY,startX);
        print_up_down(a, startX + 1, endX, endY);
        print_right_left(a, endY - 1, startY, endX);
        print_down_up(a, endX - 1, startX + 1, startY);

        startX++;
        endX--;
        startY++;
        endY--;
    }//when breaks,one line remains
    if (endX == startX&&endY != startY)
    {
        //std::cout << "print between x=" << endX << " y=" << startY << " & " << endY;
        print_left_right(a, startY, endY, startX);
    }
    else if (endX != startX&&endY == startY)
    {
        //std::cout << "print between x=" << endX << " y=" << startY << " & " << endY;
        print_up_down(a, startX, endX, startY);
    }
    else if (startX == endX&&startY == endY)
        std::cout << a[startX][startY];
}


接着写具体的函数:

void print_left_right(int a[][100], int start, int end, int x)//y goes up
{
    if ( start > end)
        return;
    for (int i = start; i <= end; i++)
    {
        std::cout << a[x][i] << " ";
    }
}
void print_right_left(int a[][100], int start, int end, int x)//x goes down
{
    if (start < end)
        return;
    for (int i = start; i >= end; i--)
    {
        std::cout << a[x][i] << " ";
    }
}
void print_up_down(int a[][100], int start, int end, int y)
{
    if ( start > end)
        return;
    for (int i = start; i <= end; i++)
    {
        std::cout << a[i][y] << " ";
    }
}
void print_down_up(int a[][100], int start, int end, int y)
{
    if (start < end)
        return;
    for (int i = start; i >= end; i--)
    {
        std::cout << a[i][y] << " ";
    }
}
void getMatrix(int a[][100],int m,int n)
{
    std::cout << "please input a matrix:" << "\n";
    for (int i = 0; i < m; i++)
    {
        for (int j = 0; j < n; j++)
            std::cin >> a[i][j];
    }
    
}
int main()
{
    int a[100][100];
    int m, n;
    std::cout << "please input number of hang:" << "\n";
    std::cin >> m;
    std::cout << "please input number of lie:" << "\n";
    std::cin >> n;
    
    //
     getMatrix(a,m, n);
     print_matrix(a, m, n);

     
}

其实写这个的时候我出了好多错误,都是泪啊
比如手抖写错了,一直没改,潜伏到最后才发现:

while (startX <= endX || startY >= startY)

尼玛第二个判断也是醉了

还有一点就是while的出口条件,我这样写可以,但是也可以是其他的,大家自己在纸上写写画画就清楚了

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