LinkedList相关用法

2019-02-22  本文已影响0人  夜阑w

一、简介

二、构造函数

  1. LinkedList(): 生成空的链表
  2. LinkedList(Collection C): 根据一个集合创建一个链表。

三、常用方法

1、增加:

2、删除:

3、查:

一个例子:

public class LinkedListDemo {
    public static void main(String[] srgs) {
        LinkedList linkedList = new LinkedList();

        linkedList.add(1);        
        linkedList.add(1, 2);      
        linkedList.addFirst(0);   
        linkedList.addLast(3);   
        linkedList.push(-1); 
        linkedList.offer(4);   
        linkedList.offerFirst(-2); 
        linkedList.offerLast(5);  

        System.out.println("LinkedList: " + linkedList); 
        linkedList.remove(); 
        System.out.println("removeFirst(): " + linkedList.removeFirst()); 
        System.out.println("removeLast(): " + linkedList.removeLast());  
        System.out.println("After remove:" + linkedList); 
        linkedList.poll();                                       
        linkedList.pollFirst();                                           
        linkedList.pollLast();                                            
        System.out.println("After poll():" + linkedList);     
        linkedList.pop();                                                
        System.out.println("After pop():" + linkedList); 
        
        linkedList.add(4);
        linkedList.add(5);
        System.out.println("get():" + linkedList.get(1));
        System.out.println("getFirst(): " + linkedList.getFirst());    
        System.out.println("getLast(): " + linkedList.getLast());        
        System.out.println("peek(): " + linkedList.peek());               
        System.out.println("peekFirst(): " + linkedList.peekFirst());  
        System.out.println("peekLast(): " + linkedList.peekLast()); 
    }
}      

输出结果:

LinkedList: [-2, -1, 0, 1, 2, 3, 4, 5]
removeFirst(): -1
removeLast(): 5
After remove:[0, 1, 2, 3, 4]
After poll():[2, 3]
After pop():[3]
get():4
getFirst(): 3
getLast(): 5
peek(): 3
peekFirst(): 3
peekLast(): 5

4、其他

import java.util.LinkedList;

public class LinkedListDemo {
    public static void main(String[] srgs) {
        LinkedList linkedList = new LinkedList();
        linkedList.add(3);
        linkedList.add(4);
        linkedList.add(5);

        // 判断此列表包含指定元素,如果是,则返回true
        System.out.println("contains(1) is :" + linkedList.contains(1)); 
        // 获取但不移除此列表的头 
        System.out.println("element(): " + linkedList.element());  
        // 返回此列表的元素个数        
        System.out.println("size is : " + linkedList.size());
        // 将此列表中指定位置的元素替换为指定的元素             
        linkedList.set(1, 3);                                             
        System.out.println("After set(1, 3):" + linkedList);
        // 返回此列表中首次出现的指定元素的索引
        System.out.println("indexOf(3): " + linkedList.indexOf(3));        
        // 返回此列表中最后出现的指定元素的索引
        System.out.println("lastIndexOf(3): " + linkedList.lastIndexOf(3));
        System.out.println("subList(2,3): " + linkedList.subList(2,3));
    }
}

输出结果:

contains(1) is :false
element(): 3
size is : 3
After set(1, 3):[3, 3, 5]
indexOf(3): 0
lastIndexOf(3): 1
subList(2,3): [5]

四、遍历

1、迭代器遍历

Iterator<Integer> iterator = linkedList.iterator();
while(iterator.hasNext()){
    iterator.next();

2、for循环get()遍历

for(int i = 0; i < linkedList.size(); i++){
    linkedList.get(i);
}

3、Foreach循环遍历

for(Integer i : linkedList) {
    // some code
};

4、通过pollFirst()或pollLast()遍历

while(linkedList.size() != 0){
    linkedList.pollFirst();
}

5、通过removeFirst()或removeLast()遍历

while(linkedList.size() != 0){
    linkedList.removeFirst();
}

注意:

import java.util.Iterator;
import java.util.LinkedList;

public class LinkedListLoop {
    public static void main(String[] args) {
        LinkedList<Integer> linkedList = new LinkedList<>();
        for(int i = 0; i < 3; i++){
            linkedList.add(i);
        }
        // 迭代器遍历
        Iterator<Integer> iterator = linkedList.iterator();
        while(iterator.hasNext()){
            System.out.println(iterator.next());;
        }

        // 顺序遍历(随机遍历)
        for(int i = 0; i < linkedList.size(); i++){
            System.out.println(linkedList.get(i));
        }

        // 另一种for循环遍历
        for(Integer i : linkedList) {
            System.out.println(i);
        };

        //  通过pollFirst()或pollLast()来遍历LinkedList
        LinkedList<Integer> temp1 = new LinkedList<>();
        temp1.addAll(linkedList);
        while(temp1.size() != 0){
            System.out.println(temp1.pollFirst());
        }

        // 通过removeFirst()或removeLast()来遍历LinkedList
        LinkedList<Integer> temp2 = new LinkedList<>();
        temp2.addAll(linkedList);
        while(temp2.size() != 0){
            System.out.println(temp2.removeFirst());
        }
    }
}
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