63. 不同路径 II
2019-03-13 本文已影响0人
cptn3m0
class Solution(object):
def uniquePathsWithObstacles(self, grid):
"""
:type obstacleGrid: List[List[int]]
:rtype: int
"""
# use a meanful name replace magic number
OBSTACLE_FLAG = 1
# guard phase
# 就是将出发点设置为一个 OBSTACLE_FLAG
if grid[0][0] == OBSTACLE_FLAG:
return 0
# grid大小 mxn
m = len(grid)
n = len(grid[0])
dp = [[0]*n for _ in range(m)]
# 这个题目的状态转移方程不难
# 需要注意的就是边界的初始化过程
# 边界条件, 这个表示开始的位置只有一个办法到达
dp[0][0] = 1
# 因为只能向下和向右走, 所以初始化一下边界条件
for i in range(1,m):
if grid[i][0] == OBSTACLE_FLAG:
break
else:
dp[i][0] = 1
for j in range(1,n):
if grid[0][j] == OBSTACLE_FLAG:
break
else:
dp[0][j] = 1
for i in range(1,m):
for j in range(1,n):
if grid[i][j] == OBSTACLE_FLAG:
dp[i][j] = 0
else:
dp[i][j] += dp[i-1][j] + dp[i][j-1]
return dp[-1][-1]