python 循环单向链表
2019-04-23 本文已影响0人
sttech
单向循环链表python实现
循环链表结点
class Node(object):
def __init__(self,item):
self.item = item
self.next = None
循环链表实现
# 单向循环链表
class SingleCycleLinkList(object):
def __init__(self):
self._head = None
def is_empty(self):
return self._head == None
def length(self):
if self.is_empty():
return 0
count = 1
cur = self._head
while cur.next != self._head:
cur = cur.next
count += 1
return count
# 遍历
def travel(self):
if self.is_empty():
return
current = self._head
strs = 'item : ' + str(current.item)
while (current.next != self._head):
current = current.next
strs = strs + ', item : ' + str(current.item)
print(strs)
头节点添加
# 头节点添加元素
def add(self,item):
node = Node(item)
if self.is_empty():
self._head = node
node.next = self._head
else:
node.next = self._head
current = self._head
while current.next != self._head:
current = current.next
current.next = node
self._head = node
尾节点添加
# 在尾部添加
def append(self,item):
node = Node(item)
if self.is_empty():
self.add(item)
current = self._head
while current.next != self._head:
current = current.next
current.next = node
node.next = self._head
插入
def insert(self,index ,item):
node = Node(item)
if index < 1:
self.add(item)
elif index > self.length() - 1:
self.append(item)
else:
present = self._head
count = 0
while count < index - 1:
present = present.next
count += 1
node.next = present.next
present.next = node
删除
# 删除item
def remove(self,item):
if self.is_empty():
return
current = self._head
while current.next != self._head:
preNode = current
current = current.next
if item != current.item:
break
else:
preNode.next = current.next
查找
# 查找
def search(self,item):
if self.is_empty():
return
current = self._head
node = None
while current.next != self._head:
current = current.next
if current.item == item:
print( 'search :' + str(item))
node = current
return node