shell的printf输出时包含空格问题

printf "%-30s:%-15s\n" report_selinux_enable $report_selinux_enable

printf "%-30s:%-15s\n" report_selinux_status $report_selinux_status

printf "%-30s:%-15s\n" report_os $report_os

printf "%-30s:%-15s\n" report_hostname $report_hostname

printf "%-30s:%-15s\n" report_kernel $report_kernel

printf "%-30s:%-15s\n" report_uptime $report_uptime

printf "%-30s:%-15s\n" report_date_time $report_date_time

输出：

report_selinux_enable :disabled

report_selinux_status :Disabled

report_os :GNU/Linux

report_hostname :centos.com

report_kernel :3.10.0-693.2.2.el7.x86_64

report_uptime :42

days :

report_date_time :2018-07-18-20-24-23

可以看出输出的在线天数（report_uptime）的值是42（本来是42 days），下面还有一行显示的有问题，把一行拆成了两行显示，是因为report_uptime的值中间有空格，所以被拆成两行

解决：printf语句后面的引用值要放在""中

printf "%-30s:%-15s\n" report_uptime "$report_uptime"

printf "%-30s:%-15s\n" "report_selinux_enable" "$report_selinux_enable"

printf "%-30s:%-15s\n" "report_selinux_status" "$report_selinux_status"

printf "%-30s:%-15s\n" "report_os" "$report_os"

printf "%-30s:%-15s\n" "report_hostname" "$report_hostname"

printf "%-30s:%-15s\n" "report_kernel" "$report_kernel"

printf "%-30s:%-15s\n" "report_uptime" "$report_uptime"

printf "%-30s:%-15s\n" "report_uptime" "$report_date_time"

report_selinux_enable :disabled

report_selinux_status :Disabled

report_os :GNU/Linux

report_hostname :centos.com

report_kernel :3.10.0-693.2.2.el7.x86_64

report_uptime :42 days

report_date_time :2018-07-18-20-27-40

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