Tornado上传文件
2018-11-01 本文已影响31人
内心强大的Jim
直接上代码
# coding: utf-8
from tornado.ioloop import IOLoop
from tornado import web
import shutil
import os
import json
class FileUploadHandler(web.RequestHandler):
def get(self):
self.write('''
<html>
<head><title>Upload File</title></head>
<body>
<form action='/file' enctype="multipart/form-data" method='post'>
<input type='file' name='file'/><br/>
<input type='submit' value='submit'/>
</form>
</body>
</html>
''')
def post(self):
ret = {'result': 'OK'}
upload_path = os.path.dirname(__file__) # 文件的暂存路径
file_metas = self.request.files.get('file', None) # 提取表单中‘name’为‘file’的文件元数据
if not file_metas:
ret['result'] = 'Invalid Args'
else:
for meta in file_metas:
filename = meta['filename']
file_path = os.path.join(upload_path, filename)
with open(file_path, 'wb') as up:
up.write(meta['body'])
# OR do other thing
self.write(json.dumps(ret))
application = web.Application([
(r'/file', FileUploadHandler),
],autoreload = True)
application.listen(8765)
IOLoop.current().start()
浏览器打开http://localhost:8765/file即可