实训总结20170916

2017-09-16  本文已影响0人  韩志俊

CREATE TABLE city(

province_code INT,

province_name string,

city_code INT,

city_name string

)

ROW FORMAT delimited

fields terminated by ','

lines terminated by '\n';

load数据到hive表: load data local inpath '/home/bigdata//hive/city.txt' into table city;

查看创建表 show create table city;

查看表信息 desc city;

修改表:alter table city rename to city_name;

复制表: create table city like city_code;

删除库 drop database **;

删除表 drop table **;

查表内容 select * from city limit 10;

显示列名 set hive.cli.print.header=true;

建库

建表

查询相关命令  最大的10个:select * from city order by city_code desc limit 10;

拥有最多市的省份:省里市的数目:取最多的10个省:

select province_name,count(city_name) as cnt from city group by province_name order by cnt desc limit 10;

去重统计 有多少个省:distinct

1)select count(distinct province_name) from city;

两重:2)select count(1)

from

(

select province_name from city group by province_name

) a;

查出只有一个市的省份:省有多少市 ;市为1

1)

select

province_name, cnt

from

(

select province_name,count(1) as cnt

from city

group by province_name

)a

where cnt =1;

2) select province_name count(1) as cnt from city group by province_name having cnt = 1;

外表:

table前加关键字external

远端要用的location'/user/hzw/city/city.txt'

create external table city_ex(

province_code int,

province_name string,

city_code int,

city_name string)

row format delimited

fields terminated by','

lines terminated by'\n'

location '/user/hzw/city/';

内表:

create table city_in(

province_code int,

province_name string,

city_code int,

city_name string)

row format delimited

fields terminated by','

lines terminated by'\n'

location '/user/hzw/city/';

2、使用分区patition对应表中的一个目录;

静态分区需要在sql语句中指定;

CREATE TABLE `user`(

`uid` INT,

`city_code` INT,

`model` string,

`access` string

)

row FORMAT delimited

fields terminated by ','

lines terminated by '\n';

load data local inpath '/home/bigdata/tanqi/hive/user.txt' into table user;

查询user: select count(*) from user;

a.静态分区:

create table user_daily(

uid int,

city_code int,

model string,

access string

)

partitioned by (p_data string);

插入数据从user :

insert overwrite table user_daily partition (p_data='2017-09-01')

select * from user;

b.动态分区

set hive.exec.dynamic.partition.mode=nonstrict;

insert overwrite table user_daily partition (p_data)

select *,'2017-09-02' from user

union all

select *,'2017-09-04' from user;

ALTER TABLE user_daily PARTITION (p_date='2017-01-01') RENAME TO PARTITION (p_date='20170101');

3.作业

a) 统计WIFI环境下用户最多的5个城市

Select city_code,count(*) as cnt from user where access='WIFI'

group by city_code order by cnt desc limit 5;

b) 统计用户数>=3的access和city_code组合

select access,city_code,count(*) as cnt from user

group by access,city_code

having cnt >=3 order by cnt desc;

c) 机型中带有ne(不区分大小写),不同access及对应用户数

select access,count(*) as cnt from user

where lower(model) like '%ne%'

group by access order by cnt desc;

判断 access里的名/总数的sum

select sum(if(access='WIFI',1,0))/count(1) from user;

select sum(if(access='2G',1,0))/count(1) from user;

select sum(if(access='4G',1,0))/count(1) from user;

if条件多

select

case

when uid % 10 in (0, 1, 2, 3) then '0-3'

when uid % 10 in (4, 5, 6, 7) then '4-7'

else '8-9'

end as interval,

count(*) as cnt

from user

group by

case

when uid % 10 in (0, 1, 2, 3) then '0-3'

when uid % 10 in (4, 5, 6, 7) then '4-7'

else '8-9'

end;

晚间

1、  list 集合

collect_set 去重的集合

collect_list 不去重

select collect_set(access) from user;

select collect_list(access) from user;

2、 hive 各种连接join

左连接 left outer join

右连接 right outer join

内连接 inner join  找出左右相同(AB相交)的记录

全连接 full join

select user.uid,user.city_code,city.city_name

from

(select * from user where uid <=100) user

left join

(select * from city where province_code <=30)city

on (user.city_code = city.city_code)

limit 20;

select user.uid,user.city_code,city.city_name

from

(select * from user where uid <=100) user

full join

(select * from city where province_code <=30)city

on (user.city_code = city.city_code)

limit 20;

3、分组top N

分组 access

排序 序号 city_code

top1 序号=1

select access,city_code,uid

from

(

select uid, access,city_code,

row_number() over (partition by access order

by city_code desc)as row_num

from user

)a

where row_num = 1;

4、累计                                                          第一行              当前行

select p_date,

sum(cnt) over(order by p_date asc rows between unbounded preceding and current row)

from

(

select p_date, count(*) as cnt

from user_daily

where p_date between '2017-09-01' and '2017-09-30'

group by p_date

)a

;

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