Android开发

JSON.parseObject的几种用法

2019-08-06  本文已影响0人  皓皓amous

以下只是草稿,较粗糙,详细的用法请参考:

FastJson对于JSON格式字符串、JSON对象及JavaBean之间的相互转换

一.result格式:

{    
   "success":"true";  
   "returnAddress":"123"
 }
   JSONObject jsonObject=JSON.parseObject(result);      //转换成object  
   jsonObject.getString("returnAddress")    //获取object中returnAddress字段;                                                       

二.result格式:

{   
      "success":"true";   
      "data":{        
               "shop_uid":"123";  
              };
 }
JSONObject shop_user =JSON.parseObject(result); JSON.parseObject(shop_user .getString("data")).getString("shop_uid")

三.result格式:

{     "success":"true";     "data":[{         "shop_uid":"123";     },     {         "shop_name":"张三"     }]}
JSONArray detail = JSON.parseArray(result);
for (int i=0; i<detail.size();i++){  
  if(detail.get(i)!=null||!detail.get(i).equals("")){   
     JSONArray detailChild =detail.getJSONArray(i);        
        if(detailChild.getInteger(1)>Integer.valueOf(ship.get("shiptime").toString())){
            ship.put("shiptime",detailChild.getInteger(1));           
            ship.put("desc",detailChild.getString(0));       
            }     
         }
      }

JSON转javaBean

1.1 JSONobject=>javaBean

JSONObject contentChild = contentsArray.getJSONObject(i);
QCCustomerScore.CustomerCore customerCore = JSON.toJavaObject(contentChild, QCCustomerScore.CustomerCore.class);

1.2 String转javaBean

见:FastJson对于JSON格式字符串、JSON对象及JavaBean之间的相互转换

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