2020-11-11-简单-1480. 一维数组的动态和

题目链接:
https://leetcode-cn.com/problems/running-sum-of-1d-array/

class Solution {
    public int[] runningSum(int[] nums) {
        for (int i = 1; i < nums.length; i++) {
            nums[i]+=nums[i-1];
        }
        return nums;
    }
}

输出当前值之前所有值的累加和