oracle 上下行某字段相减

2020-10-20  本文已影响0人  平面小狮子
select
   a.active_time,b.active_time,(a.active_time - b.active_time),a.num,b.num
from
   (select row_number() over (order by t.create_time desc) num,t.* from YB_WC_MONITOR t) a,
   (select row_number() over (order by t1.create_time desc) num,t1.* from YB_WC_MONITOR t1) b
where
   a.num=b.num-1;
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