2019-01-25 20以内简单运算

原创来自https://www.jianshu.com/p/86e3d5b21eba

import random

ROW = 26            # 表格的行数
COL = 5             # 表格的列数
COUNT = ROW * COL    # 行×列，一张试卷总共题目的数量

Answer100 = []      # 数组初始化
for i in range(0, COUNT):
    Answer100.append(0)

# n 是表格的行数，通过 n 可以方便计算数组下标，把答案写入Answer100[]中
def printLine(n):
    output = '| '       # 该行中第一个 “|”
    count = 0

    while (count<COL):
        a = random.randint(1, 20)
        b = random.randint(1, 20)
        c = random.randint(1,20)
        op1 = random.randint(0, 1)  # +/-
        op2 = random.randint(0, 1)

        if op1 == 0 and op2==1 and (a + b-c) < 20 and (b>c) and (b-c)>0:   # ADD
            # print('%d  +  %d  = ' % (num1, num2), ' | ', end='')
            count += 1
            Answer100[n * COL + count - 1] = a + b - c
            output += str(a) + ' + ' + str(b) + ' - ' + str(c) + ' =   | '

        if op1 == 1 and op2 == 0 and (a > b) and (a - b) > 0 and (a - b + c) < 20:     # SUB
            # print('%d  -  %d  = ' % (num1, num2), ' | ', end='')
            count += 1
            Answer100[n * COL + count - 1] = a - b + c
            output += str(a) + ' - ' + str(b) + ' + '+ str(c) + ' =   | '

        if op1 == 0 and op2 == 0 and (a + b + c) < 20:     # SUB
            # print('%d  -  %d  = ' % (num1, num2), ' | ', end='')
            count += 1
            Answer100[n * COL + count - 1] = a + b + c
            output += str(a) + ' + ' + str(b) + ' + '+ str(c) + ' =   | '

        if op1 == 1 and op2 == 1 and (a > b) and (a - b) > 0 and (b > c) and (b - c) > 0 and (a - b) > c and (a - b - c) < 20:     # SUB
            # print('%d  -  %d  = ' % (num1, num2), ' | ', end='')
            count += 1
            Answer100[n * COL + count - 1] = a - b - c
            output += str(a) + ' - ' + str(b) + ' - '+ str(c) + ' =   | '

    output += '\n'
    return output


with open("简单运算.md", 'w') as f:  # 写到硬盘中的 简单运算.md 文件中
    f.write(printLine(0))  # 表格标题行

    f.write('| ------- | ------- | ------- | ------- | ------- |\n')
    # 表格分隔行，全是字符
    # 其实这里应该根据 COL 的数量来判断中间几个 “----” 的
    # 但是好像在Typora 中，这个错了不影响表格，那就这么样吧，懒得弄了

    for i in range(1, ROW):  # 写后面的内容行
        f.write(printLine(i))

    # 答案写在另一页，先来个二级标题
    f.write('## Answer \n')

    # 答案的标题行
    f.write('| ' + str(Answer100[0]) + ' | '
            + str(Answer100[1]) + ' | '
            + str(Answer100[2]) + ' | '
            + str(Answer100[3]) + ' | '
            + str(Answer100[4]) + ' | \n')
    # 答案的分隔行
    f.write('| ---- | ---- | ---- | ---- | ---- |\n')

    # 答案剩下的行
    for i in range(1, ROW):
        f.write('| ' + str(Answer100[i * 5]) + ' | '
                + str(Answer100[i * 5 + 1]) + ' | '
                + str(Answer100[i * 5 + 2]) + ' | '
                + str(Answer100[i * 5 + 3]) + ' | '
                + str(Answer100[i * 5 + 4]) + ' | \n')