django自带分页
2017-07-18 本文已影响0人
赖三石
urls.py
from django.conf.urls import url
from django.contrib import admin
from app01 import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^index/', views.index, name='index'),
]
views.py
# encoding=utf-8
from django.shortcuts import render
from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
def index(request):
#模拟数据,列表生成式
a_list = [i for i in range(1, 1003)]
paginator = Paginator(a_list, 8) # Show 25 contacts per page
page = request.GET.get('page')
try:
data = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
data = paginator.page(1)
except EmptyPage:
# If page is out of range (e.g. 9999), deliver last page of results.
data = paginator.page(paginator.num_pages)
return render(request,'index.html',{
'data': data
})
template
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
<style>
.active{
background-color: #1b6d85;
}
#ss li{
float: left;
display: inline;
margin-left: 10px;
}
</style>
</head>
<body>
<ul>
{% for d in data %}
<li>{{ d }}</li>
{% endfor %}
</ul>
{#{% for i in page %}#}
{#{{ i|safe }}#}
{#{% endfor %}#}
<ul id="ss">
{% if data.has_previous %}
<li><a href="/index/?page={{ data.previous_page_number }}" >上一页</a></li>
{% endif %}
{% for p_num in data.paginator.page_range %}
{% if data.number == p_num %}
<li><a class="active" href="/index/?page={{ p_num }}">{{ p_num }}</a></li>
{% else %}
<li><a href="/index/?page={{ p_num }}">{{ p_num }}</a></li>
{% endif %}
{% endfor %}
{% if data.has_next %}
<li><a href="/index/?page={{ data.next_page_number }}" >下一页</a></li>
{% endif %}
</ul>
</body>
</html>
