145. 二叉树的后序遍历
2019-12-30 本文已影响0人
Andysys
// 递归
public List<Integer> postorderTraversal1(TreeNode root) {
List<Integer> list = new LinkedList<>();
helper(root, list);
return list;
}
private void helper(TreeNode node, List<Integer> list) {
if (node == null) {
return;
}
if (node.left != null) {
helper(node.left, list);
}
if (node.right != null) {
helper(node.right, list);
}
list.add(node.val);
}
// 迭代
public List<Integer> postorderTraversal2(TreeNode root) {
LinkedList<Integer> output = new LinkedList<>();
if (root == null) {
return output;
}
LinkedList<TreeNode> stack = new LinkedList<>();
stack.add(root);
TreeNode node = null;
while (!stack.isEmpty()) {
node = stack.pollLast();
output.addFirst(node.val);
if (node.left != null) {
stack.add(node.left);
}
if (node.right != null) {
stack.add(node.right);
}
}
return output;
}