python列表--查找集合中重复元素的个数

方法一：

>>> mylist = [1,2,2,2,2,3,3,3,4,4,4,4]

>>> myset = set(mylist)

>>> for item in myset:

         print("the %d has found %d" %(item,mylist.count(item)))

the 1 has found 1

the 2 has found 4

the 3 has found 3

the 4 has found 4

方法二：

>>> from collections import Counter

>>> Counter([1,2,2,2,2,3,3,3,4,4,4,4])

Counter({2: 4, 4: 4, 3: 3, 1: 1})

方法三：

>>> List=[1,2,2,2,2,3,3,3,4,4,4,4]

>>> a = {}

>>> for i in List:

         if List.count(i)>1:

                   a[i] = List.count(i)

        

>>> print (a)

# most_common(n) 按照counter的计数，按照降序，返回前n项组成的list; n忽略时返回全部
>>> Counter('abracadabra').most_common(3)
[('a', 5), ('r', 2), ('b', 2)]

参考资料：
# python列表--查找集合中重复元素的个数

https://www.cnblogs.com/nisen/p/6052895.html