383. Ransom Note

2018-10-13  本文已影响0人  SilentDawn

Problem

Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.

Example

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

Code

static int var = [](){
    std::ios::sync_with_stdio(false);
    cin.tie(NULL);
    return 0;
}();
class Solution {
public:
    bool canConstruct(string ransomNote, string magazine) {
        long table[256] = {0};
        for(int i=0;i<magazine.size();i++){
            table[magazine[i]]++;
        }
        for(int i=0;i<ransomNote.size();i++){
            if((--table[ransomNote[i]])<0)
                return false;
        }
        return true;
    }
};

Result

383. Ransom Note.png
上一篇下一篇

猜你喜欢

热点阅读