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Flutter-为什么包装一层Builder控件之后,路由或点击

2019-10-10  本文已影响0人  XuYanjun

事故回放

一朋友面试,被问到在Flutter中一些因 context 引起的路由异常的问题,为什么包装一层 Builder 控件之后,路由或点击弹框事件正常使用了?然后就没然后了。。。相信很多人都会用,至于为什么,也没深究。

相信很多刚开始玩Flutter的同学都会在学习过程中都会写到类似下面的这种代码:

import 'package:flutter/material.dart';

class BuilderA extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      home: Scaffold(
        body: GestureDetector(
          onTap: () {
            Scaffold.of(context).showSnackBar(SnackBar(
              content: Text('666666'),
            ));
          },
          child: Center(
            child: Container(
              width: 100,
              height: 100,
              color: Colors.red,
            ),
          ),
        ),
      ),
    );
  }
}

开开心心写完,然后一顿运行:

void main() => runApp(BuilderA());

点击,发现 SnackBar 并没有正常弹出,而是出现了下面这种异常:

════════ Exception caught by gesture
═══════════════════════════════════════════════════════════════

The following assertion was thrown while handling a gesture:

<font color=red>Scaffold.of() called with a context that does not contain a Scaffold.</font>

...

网上很多资料都说需要外包一层 Builder 可以解决这种问题,但是基本上没说原因,至于为什么说可以外包一层 Builder 就可以解决,我想大部分只是看了 Scaffold 的源码中的注释了解到的:

scaffold.dart 第1209行到1234行:
...
/// {@tool snippet --template=stateless_widget_material}
/// When the [Scaffold] is actually created in the same `build` function, the
/// `context` argument to the `build` function can't be used to find the
/// [Scaffold] (since it's "above" the widget being returned in the widget
/// tree). In such cases, the following technique with a [Builder] can be used
/// to provide a new scope with a [BuildContext] that is "under" the
/// [Scaffold]:
///
/// ```dart
/// Widget build(BuildContext context) {
///   return Scaffold(
///     appBar: AppBar(
///       title: Text('Demo')
///     ),
///     body: Builder(
///       // Create an inner BuildContext so that the onPressed methods
///       // can refer to the Scaffold with Scaffold.of().
///       builder: (BuildContext context) {
///         return Center(
///           child: RaisedButton(
///             child: Text('SHOW A SNACKBAR'),
///             onPressed: () {
///               Scaffold.of(context).showSnackBar(SnackBar(
///                 content: Text('Have a snack!'),
///               ));
///             },
...

那到底是什么原因外包一层 Builder 控件就可以了呢?


原因分析

异常原因

上面那种写法为什么会异常?要想知道这个问题,我们首先看这句描述:

Scaffold.of() called with a context that does not contain a Scaffold.

意思是说在不包含Scaffold的上下文中调用了Scaffold.of()

我们仔细看看这个代码,会发现,此处调用的 contextBuilderA 的,而在BuilderA中的 build 方法中我们才指定了 Scaffold ,因此确实是不存的。

为什么包一层Builder就没问题了?

我们把代码改成下面这种:

class BuilderB extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      home: Scaffold(
        body: Builder(
          builder: (context) => GestureDetector(
            onTap: () {
              Scaffold.of(context).showSnackBar(SnackBar(
                content: Text('666666'),
              ));
            },
            child: Center(
              child: Container(
                width: 100,
                height: 100,
                color: Colors.red,
              ),
            ),
          ),
        ),
      ),
    );
  }
}

运行之后发现确实没问题了?为什么呢?我们先来看看 Builder 源码:

// ##### framework.dart文件下
typedef WidgetBuilder = Widget Function(BuildContext context);


// ##### basic.dart文件下
class Builder extends StatelessWidget {
  /// Creates a widget that delegates its build to a callback.
  ///
  /// The [builder] argument must not be null.
  const Builder({
    Key key,
    @required this.builder,
  }) : assert(builder != null),
       super(key: key);

  /// Called to obtain the child widget.
  ///
  /// This function is called whenever this widget is included in its parent's
  /// build and the old widget (if any) that it synchronizes with has a distinct
  /// object identity. Typically the parent's build method will construct
  /// a new tree of widgets and so a new Builder child will not be [identical]
  /// to the corresponding old one.
  final WidgetBuilder builder;

  @override
  Widget build(BuildContext context) => builder(context);
}

代码很简单,Builder 类继承 StatelessWidget ,然后通过一个接口回调将自己对应的 context 回调出来,供外部使用。没了~
但是!外部调用:

onTap: () {
  Scaffold.of(context).showSnackBar(SnackBar(
    content: Text('666666'),
  ));
}

此时的 context 将不再是 BuilderBcontext 了,而是 Builder 自己的了!!!

那么问题又来了~~~凭什么改成 Builder 中的 context 就可以了?我能这个时候就不得不去看看 Scaffold.of(context) 的源码了:

...

static ScaffoldState of(BuildContext context, { bool nullOk = false }) {
    assert(nullOk != null);
    assert(context != null);
    final ScaffoldState result = context.ancestorStateOfType(const TypeMatcher<ScaffoldState>());
    if (nullOk || result != null)
      return result;
    throw FlutterError(
      
...省略不重要的
  @override
  State ancestorStateOfType(TypeMatcher matcher) {
    assert(_debugCheckStateIsActiveForAncestorLookup());
    Element ancestor = _parent;
    while (ancestor != null) {
      if (ancestor is StatefulElement && matcher.check(ancestor.state))
        break;
      ancestor = ancestor._parent;
    }
    final StatefulElement statefulAncestor = ancestor;
    return statefulAncestor?.state;
  } 

上面的核心部分揭露了原因:
of() 方法中会根据传入的 context 去寻找最近的相匹配的祖先 widget,如果寻找到返回结果,否则抛出异常,抛出的异常就是上面出现的异常!

此处,Builder 就在 Scafflod 节点下,因在 Builder 中调用 Scafflod.of(context) 刚好是根据 Builder 中的 context 向上寻找最近的祖先,然后就找到了对应的 Scafflod,因此这也就是为什么包装了一层 Builder 后就能正常的原因!

总结时刻

当然,处理这类问题不仅仅这一种思路,道路千万条,找到符合自己的那一条才是关键!

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