R 数据管理

2018-12-20  本文已影响21人  Thinkando

for, while, if-else,ifelse,switch

> #1 for
> for (i in 1:10) print("good")
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"
[1] "good"

> x<-c(2,5,8)
> for (i in x) print(i^2)
[1] 4
[1] 25
[1] 64

> #2 while
> i<-1
> while (i<=10) {print("second");i<-i+1}
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
[1] "second"
> while(TRUE) {i<-i+1 
+ if(i>10) break}
> i<-1
> repeat {i<-i+1
+ if (i>10) break}
> i
[1] 11

> #3 if-else
> data("cohesion")
> if (is.numeric(cohesion$COHO2)) cohension$COHO6 <-"study"
> if (is.numeric(cohesion$COHO2)) cohension$COHO6 <-"study" else cohension$COHO6 <-"secondtrial"

> x<-4
> y<- if (x==2) x else x+1
> y
[1] 5

> #4 ifelse
> x<-1
> ifelse(x>2,x+1,x+5)
[1] 6

> #5 switch
> feelings <-c("a","b")
> for (i in feelings)
+ print(switch (i,
+               a="sad",
+               b="happy"))
[1] "sad"
[1] "happy"

实例

> studentname <- c("John Davis", "Angela Williams", "Bullwinkle Moose", "David Jones", "Janice Markhammer", "Cheryl Cushing", "Reuven Ytzrhak", "Greg Knox", "Joel England", "Mary Rayburn")
> math <-  c(502, 600, 412, 358, 495, 512, 410, 625, 573, 522)
> science  <- c(95, 99, 80, 82, 75, 85, 80, 95, 89, 86)
> English  <- c(25, 22, 18, 15, 20, 28, 15, 30, 27,18)
> scoredata  <- data.frame(studentname, math, science, English, stringsAsFactors=FALSE)
> z  <- scale(scoredata[2:4]) # scale把数据标准化,用于比较
> z
             math     science     English
 [1,]  0.01269128  1.07806562  0.58685145
 [2,]  1.14336936  1.59143020  0.03667822
 [3,] -1.02568654 -0.84705156 -0.69688609
 [4,] -1.64871324 -0.59036927 -1.24705932
 [5,] -0.06807144 -1.48875728 -0.33010394
 [6,]  0.12806660 -0.20534583  1.13702468
 [7,] -1.04876160 -0.84705156 -1.24705932
 [8,]  1.43180765  1.07806562  1.50380683
 [9,]  0.83185601  0.30801875  0.95363360
[10,]  0.24344191 -0.07700469 -0.69688609
attr(,"scaled:center")
   math science English 
  500.9    86.6    21.8 
attr(,"scaled:scale")
     math   science   English 
86.673654  7.791734  5.452828 

> Score  <-  apply(z, 1, mean) # apply 函数可以并行
> scoredata2  <- cbind(scoredata, Score) # 把Score 添到 scoredata 后面
> scoredata2
         studentname math science English      Score
1         John Davis  502      95      25  0.5592028
2    Angela Williams  600      99      22  0.9238259
3   Bullwinkle Moose  412      80      18 -0.8565414
4        David Jones  358      82      15 -1.1620473
5  Janice Markhammer  495      75      20 -0.6289776
6     Cheryl Cushing  512      85      28  0.3532485
7     Reuven Ytzrhak  410      80      15 -1.0476242
8          Greg Knox  625      95      30  1.3378934
9       Joel England  573      89      27  0.6978361
10      Mary Rayburn  522      86      18 -0.1768163

> y <- quantile(Score, c(0.8,0.6,0.4,0.2)) # 百分比
> y
       80%        60%        40%        20% 
 0.7430341  0.4356302 -0.3576808 -0.8947579 
> # ABCDE 分等级评分
> scoredata2$grade [Score >=y[1]]  <-"A"
> scoredata2$grade [Score < y[1] & Score >=y[2]]  <-"B"
> scoredata2$grade [Score < y[2] & Score >=y[3]]  <-"C"
> scoredata2$grade [Score < y[3] & Score >=y[4]]  <-"D"
> scoredata2$grade [Score < y[4]]  <-  "E"
> scoredata2
         studentname math science English      Score grade
1         John Davis  502      95      25  0.5592028     B
2    Angela Williams  600      99      22  0.9238259     A
3   Bullwinkle Moose  412      80      18 -0.8565414     D
4        David Jones  358      82      15 -1.1620473     E
5  Janice Markhammer  495      75      20 -0.6289776     D
6     Cheryl Cushing  512      85      28  0.3532485     C
7     Reuven Ytzrhak  410      80      15 -1.0476242     E
8          Greg Knox  625      95      30  1.3378934     A
9       Joel England  573      89      27  0.6978361     B
10      Mary Rayburn  522      86      18 -0.1768163     C

> name <- strsplit((scoredata2$studentname), " ")
> name
> lastname  <-sapply(name, "[", 2) # "[" 是一个可以提取某个对象一部分的函数
> firstname <-sapply(name, "[", 1)
> scoredata3 <- cbind(firstname, lastname, scoredata2[,-1]) # 特异性插入
> scoredata3
    firstname   lastname math science English      Score grade
1        John      Davis  502      95      25  0.5592028     B
2      Angela   Williams  600      99      22  0.9238259     A
3  Bullwinkle      Moose  412      80      18 -0.8565414     D
4       David      Jones  358      82      15 -1.1620473     E
5      Janice Markhammer  495      75      20 -0.6289776     D
6      Cheryl    Cushing  512      85      28  0.3532485     C
7      Reuven    Ytzrhak  410      80      15 -1.0476242     E
8        Greg       Knox  625      95      30  1.3378934     A
9        Joel    England  573      89      27  0.6978361     B
10       Mary    Rayburn  522      86      18 -0.1768163     C

scoredata4 <-scoredata3 [order(lastname, firstname),] # order 排序
scoredata4
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