面试算法

牛客-剑指0ffer-平衡二叉树

2019-08-08  本文已影响2人  wenyilab

题目描述
输入一棵二叉树,判断该二叉树是否是平衡二叉树。

class Solution {
public:
    bool IsBalanced_Solution(TreeNode* pRoot) {
        if (pRoot == NULL) return true;
        
        int left = TreeDepth(pRoot->left);
        int right = TreeDepth(pRoot->right);
        int diff = left - right;
        
        if (diff > 1 || diff < -1){
            return false;
        }
        return IsBalanced_Solution(pRoot->left) && IsBalanced_Solution(pRoot->right);

    }
    int TreeDepth(TreeNode* pRoot){
        if (pRoot == NULL) return 0;
        int left = TreeDepth(pRoot->left);
        int right = TreeDepth(pRoot->right);
        
        return (left>right)?(left+1):(right+1);
    }
};
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