swift 字符串和字符

2021-06-07  本文已影响0人  JianLee

swift的String类型是值类型。如果您创建了一个新的字符串,那么当其进行常量、变量赋值操作,或在函数或方法中传递时,会进行值拷贝。 任何情况下,都会对已有字符串值创建新副本,并对该新副本进行传递或赋值操作

字符串的初始化

var emptyString = ""           //通过字面量初始化空字符串
let someString = "hello world" //通过字面量初始化字符串

var anotherEmptyString = String()  // 初始化方法

//Character的数组初始化字符串
let charactersStr: [Character] = ["s", "w", "i", "f", "t"]
let str = String(charactersStr)

字符串判空

使用isEmpty属性

if keyNote.isEmpty {
    print("空空如也")
}

多行字符串

由一对三个双引号 """包裹着的具有固定顺序的文本字符集

let str = """
空有人间自由身

却非人间自由人
"""
print(str)

log:
空有人间自由身

却非人间自由人

可变字符串(var)

swift中的可变字符串与OC中的可变字符串不同,OC在两个类(NSString和NSMutableString)之间进行选择,swift用let和var作区别,类似kotlin的 val和var

var message = "产品经理"
message += "要怎样?"  //产品经理要怎样?

计算字符串长度(count)

print(string.count)    

字符串遍历

for character in "swift" {
    print(character)
}

log:
s
w
i
f
t
let someString = "dog"
for index in someString.indices {
    print(someString[index])
}
// d
// o
// g

字符串中插入值

var varA   = 20
let constA = 100
var varC:Float = 20.0

var stringA = "\(varA) 乘于 \(constA) 等于 \(varC * 100)"
print( stringA )

以上程序执行输出结果为:

20 乘于 100 等于 2000.0

字符串拼接

let message = "产品经理"
let result = "\(message)要怎样?"  //产品经理要怎样?
let str1 = "产品经理"
let str2 = "要怎样?"
var message = str1 + str2 //产品经理要怎样?

var message = "产品经理"
message += "要怎样?"  //产品经理要怎样?
let mark: Character = "?"
var string = "产品经理要怎样"
string.append(mark)  //产品经理要怎样?
let mark: Character = "?"
var string = "产品经理要怎样"
string.append(mark)  //产品经理要怎样?

字符串的索引

let someString = "developer"
print(someString[someString.startIndex])    //d
print(someString[someString.index(before: someString.endIndex)])    //r
print(someString[someString.index(after: someString.startIndex)])   //e
let index = someString.index(someString.startIndex, offsetBy: 5)
print(someString[index])    //o

字符串的插入

var someString = "developer"
someString.insert("!", at: someString.endIndex)
// someString = developer!

var someString = "developer"
someString.insert(contentsOf: "are great", at: someString.endIndex)
// someString = developer are great

字符串的删除

var someString = "developer!"
someString.remove(at:someString.index(before: someString.endIndex))
// someString = developer
let range = someString.index(someString.endIndex, offsetBy: -10) ..< someString.endIndex
someString.removeSubrange(range)
// someString = developer

字符串替换

let str = "aa$$bb$$cc$$dd"
let str2 = str.replacingOccurrences(of: "$$", with: "**")  
//aa**bb**cc**dd

字符串截取

Swift 里的 SubString 绝大部分函数都跟 String 一样,意味着你可以使用同样的方式去操作 SubString 和 String。然而,String 和 SubString 的区别在于性能优化上,SubString 可以重用原 String 的内存空间,或者另一个 SubString 的内存空间(String 也有同样的优化,但如果两个 String 共享内存的话,它们就会相等)。这一优化意味着你在修改 String 和 SubString 之前都不需要消耗性能去复制内存。 因为它重用了原 String 的内存空间,原 String 的内存空间必须保留直到它的 SubString 不再被使用为止你只有在短时间内需要操作字符串时,才会使用 SubString。当你需要长时间保存结果时,就把 SubString 转化为 String 的实例


image.png
let str = "developer"
let index = str.firstIndex(of: "v") ?? str.endIndex
let sub = str[...index]    //dev
let sub1 = str[index ..< str.endIndex]    //veloper
let sub2 = str[str.startIndex ..< index]  //de

// 把结果转化为 String 以便长期存储
let newString = String(sub)

str 是一个 String,意味着它在内存里有一片空间保存字符集。而由于 sub 是 str 的 SubString,它重用了 str 的内存空间。相反,newString 是一个 String —— 它是使用 SubString 创建的,拥有一片自己的内存空间

比较字符串

let str1 = "develop are great"
let str2 = "develop are great"
if str1 == str2 {
   print("字符串相同")
}
let romeoAndJuliet = [
    "Act 1 Scene 1: Verona, A public place",
    "Act 1 Scene 2: Capulet's mansion",
    "Act 1 Scene 3: A room in Capulet's mansion",
    "Act 2 Scene 1: Outside Capulet's mansion",
    "Act 2 Scene 2: Capulet's orchard",
    "Act 2 Scene 3: Outside Friar Lawrence's cell"
]
var act1SceneCount = 0
for scene in romeoAndJuliet {
    if scene.hasPrefix("Act 1 ") {
        act1SceneCount += 1
    }
}
print("There are \(act1SceneCount) scenes in Act 1")
//There are 3 scenes in Act 1

var mansionCount = 0
var cellCount = 0
for scene in romeoAndJuliet {
    if scene.hasSuffix("Capulet's mansion") {
        mansionCount += 1
    } else if scene.hasSuffix("Friar Lawrence's cell") {
        cellCount += 1
    }
}
print("\(mansionCount) mansion scenes; \(cellCount) cell scenes")
//3 mansion scenes; 1 cell scenes

字面量中的特殊字符

let wiseWords = "\"Imagination is more important than knowledge\" - Einstein"
let dollarSign = "\u{24}"        
let blackHeart = "\u{2665}"      
let sparklingHeart = "\u{1F496}" 

print(wiseWords)  // "Imagination is more important than knowledge" - Einstein
print(dollarSign)  // $,  Unicode scalar U+0024
print(blackHeart)  // ♥,  Unicode scalar U+2665
print(sparklingHeart)  // 💖, Unicode scalar U+1F496

Swift 字符(Character)

import Cocoa

let char1: Character = "A"
let char2: Character = "B"

print("char1 的值为 \(char1)")
print("char2 的值为 \(char2)")

以上程序执行输出结果为:

char1 的值为 A
char2 的值为 B

如果你想在 Character(字符) 类型的常量中存储更多的字符,则程序执行会报错,如下所示:

// Swift 中以下赋值会报错
let char: Character = "AB"
print("Value of char \(char)")

Swift 中不能创建空的 Character(字符) 类型变量或常量:

// Swift 中以下赋值会报错
let char1: Character = ""
var char2: Character = ""
print("char1 的值为 \(char1)")
print("char2 的值为 \(char2)")
//Swift 3 中:
for ch in "Runoob".characters {
    print(ch)
}
//Swift 4 中:
for ch in "Runoob" {
    print(ch)
}
var varA:String = "Hello "
let varB:Character = "G"
varA.append( varB )
print("varC  =  \(varA)")
//以上程序执行输出结果为:
//varC  =  Hello G
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