LeeCode题目笔记

2019-09-07 有效的数独

2019-09-28  本文已影响0人  Antrn

判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

  1. 数字 1-9 在每一行只能出现一次。
  2. 数字 1-9 在每一列只能出现一次。
  3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。
示例图像

上图是一个部分填充的有效的数独。

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

输入:

[
  ["5","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]

输出: true

示例 2:

输入:

[
  ["8","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]

输出: false

解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。</pre>

说明:

C++ *
class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
        int k=0;
        while(k<9){
            vector<char> m;
            for(int i=0;i<3;i++){
                for(int j=0;j<3;j++){
                    if(board[k/3*3+i][k%3*3+j] != '.'){
                        m.push_back(board[k/3*3+i][k%3*3+j]);
                    }
                }
            }
            for(int p=0;p<m.size();p++){
                for(int y=p+1;y<m.size();y++){
                    if(m[p] == m[y]){
                        return false;
                    }
                }
            }
            k++;
        }
        for(int i=0;i<board.size();i++){
            for(int j=0;j<board[i].size();j++){
                for(int k=j+1;k<board[i].size();k++){
                    if(board[i][j] == board[i][k] && board[i][j] != '.'){
                        return false;
                    }
                }
            }
        }
        for(int i=0;i<9;i++){
            for(int j=0;j<9;j++){
                for(int k=j+1;k<9;k++){
                    if(board[j][i] == board[k][i] && board[j][i] != '.'){
                        return false;
                    }
                }
            }
        }
        return true;
    }
};
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