Swift 按创建日期排序的文件列表

2021-02-20  本文已影响0人  花漾爱意
  1. 获取文件列表

    public func getAllFile() -> [String] {
        var filePaths = [String]()
        do {
            var array = try FileManager.default.contentsOfDirectory(atPath: getFilePath())
            sortFileArray(sort: &array)
            for fileName in array {
                var isDir: ObjCBool = true
                let fullPath = getFilePath() + fileName
                if FileManager.default.fileExists(atPath: fullPath, isDirectory: &isDir) {
                    if !isDir.boolValue, fileName.hasSuffix("plist") {
                        let fileInfo = try FileManager.default.attributesOfItem(atPath: fullPath)
                        print("fileInfo[creationDate]   \(fileInfo[.creationDate])")
                        filePaths.append(fileName)
                    }
                }
            }
        } catch let error as NSError {
            print("error \(error)")
        }
        return filePaths
    }
    private func getFilePath() -> String {
        NSSearchPathForDirectoriesInDomains(.documentDirectory, .userDomainMask, true).first! + "/"
    }
    
  1. 按照创建日期进行排序

    fileprivate func sortFileArray(sort array:inout [String]){
        for i in 0 ..< array.count {
            for j in i + 1 ..< array.count {
                let fullPath = getFilePath() + array[i]
                let nextPath = getFilePath() + array[j]
                do {
                    if let fileDate = try FileManager.default.attributesOfItem(atPath: fullPath)[.creationDate] as? Date
                    ,let nextDate = try FileManager.default.attributesOfItem(atPath: nextPath)[.creationDate] as? Date,
                       fileDate.compare(nextDate) == .orderedAscending{
                        exchangeValue(&array, i, j)
                    }
                } catch let error as NSError {
                    print("error  \(error)")
                }
            }
        }
    }
    fileprivate func exchangeValue<T>(_ nums:inout [T],_ a:Int,_ b:Int){
        (nums[a],nums[b]) = (nums[b],nums[a])
    }
    
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