猜正数游戏，用户给出要猜的数和至多可猜的次数

代码

//猜正数游戏，用户给出要猜的数和至多可猜的次数

#include<stdio.h>

int main()
{
    int num,n;
    int guessNum;
    int cnt = 0;
    int finished = 0;
    
    printf("input num and n: ");
    scanf("%d %d",&num,&n);
    printf("start guess:\n");
    do
    {
        if(cnt>=n)
        {
            finished = 1;
            printf("%d times,game over!\n",n);
        }
        else
        {
        scanf("%d",&guessNum);
        cnt++;
        if(guessNum<0)
        {
            finished = 1;
        }
        else if(guessNum>num)
        {
            printf("too big!\n");
        }
        else if(guessNum<num)
        {
            printf("too small!\n");
        }
        else
        {
            if(cnt==1)
            {
                printf("bingo!\n");
            }
            else if(cnt<=3)
            {
                printf("lucky you!\n");
            }
            else
            {
                printf("good guess!\n");
            }
            finished = 1;
        }
        }
    }while(!finished);
        
    return 0;
} 

输出

输出.PNG

求前n项的和

//求序列前n项和：2/1+3/2+5/3+8/5+...

#include<stdio.h>

int main()
{
    int n,i;
    double divident = 2, divisor = 1;
    double t;
    double sum = 0;
    
    printf("input n: ");
    scanf("%d",&n);     
    for(i=1;i<=n;i++)
    {
        sum +=divident/divisor;
        t = divident;
        divident = divident+divisor;
        divisor = t;    
    }
    printf("%.2f",sum);
    return 0;
 } 

输出

输出.PNG

约分最简分式：2/4->1/2

//约分最简分式

#include<stdio.h>

int main()
{
    int divident,divisor;
    int t;
    int a,b;
    
    printf("input divident/divisor,like 4/8: ");
    scanf("%d/%d",&divident,&divisor);
    //辗转相除法求最大公约数
    a = divident;
    b = divisor;
    while(b!=0)
    {
        t = a%b;
        a = b;
        b = t;
    }
    printf("最大公约数:%d\n",a);
    printf("最简分式:%d/%d",divident/a,divisor/a);
    
    return 0;
 } 

输出

输出.PNG

输出数字对应的拼音:200->er ling ling, -4->fu si

//输出数字对应的拼音:200->er ling ling, -4->fu si

#include<stdio.h>

int main()
{
    int x,t,d;
    int mask = 1;
    
    printf("input x: ");
    scanf("%d",&x); 
    if(x<0)
    {
        x = -x;
        printf("fu ");
    }
    t = x;
    //求可用来除的最大倍数 
    while(t>9)
    {
        t /=10;
        mask = mask*10;
    }
    do
    {
        d = x/mask;
        switch(d)
        {
            case 0: printf("ling");break;
            case 1: printf("yi");break;
            case 2: printf("er");break;
            case 3: printf("san");break;
            case 4: printf("si");break;
            case 5: printf("wu");break;
            case 6: printf("liu");break;
            case 7: printf("qi");break;
            case 8: printf("ba");break;
            case 9: printf("jiu");break;
        }
        if(mask>9)
        {
            printf(" ");    
        }
        x = x%mask;
        mask = mask/10;     
    }while(mask>0); 
    
    return 0;
 } 

输出

输出.PNG

求 输入a,n,计算a+aa+aaa+aaaa+...

//输入a,n,计算a+aa+aaa+aaaa+...
//如输入2,4 输出2+22+222+2222的和

#include<stdio.h>

int main()
{
    int a,n;
    int i;
    int sum = 0;
    int t = 0;
    
    printf("input a and n:\n");
    scanf("%d %d",&a,&n);   
    for(i = 1;i<=n;i++)
    {
        t = t*10+a;
        sum +=t;
    }
    
    printf("\nsum=%d",sum);
    
    return 0;
 } 

输出

输出.PNG