实现Promise串行
2020-06-01 本文已影响0人
我才不鸟你呢
前几天做总结，看到这个问题，多个Promise串行，梳理一下
var promiseArray = [new Promise((resolve,reject)=>{console.log('1')}),new Promise((resolve,reject)=>{console.log('2')}),new Promise((resolve,reject)=>{console.log('3')}),new Promise((resolve,reject)=>{console.log('4')}),new Promise((resolve,reject)=>{console.log('5')})];
1.原始简单方法
let arry1= [];
for(var i = 0; i<promiseArray.length-1; i++){
promiseArray[i]().then(result=>{
arry1.push(result);
console.log(result);
});
console.log(arry1);
}
2.借助 async/await串行
let p = Promise.resolve();
for(var i = 0; i<promiseArray.length-1; i++){
p(promiseArray[i]()).then(result=>{
arr1.push(result)
})
console.log(arry1);
}
