iOS

Swift之可选项

2019-07-05  本文已影响6人  eagleyz

本文首发于我的个人博客

定义

var name: String? = "Jack"
name = nil


var age: Int? // 默认就是nil 
age = 10
age = nil

强制解包

var age: Int? // 默认就是nil 
age = 10
age = nil

var age: Int? = 10
let ageInt: Int = age!
ageInt += 10

var age: Int?
age!// 报错:Fatal error: Unexpectedly found nil while unwrapping an Optional value

判断可选项是否包含值


let number = Int("123")
if number != nil {
    print("字符串转换整数成功:\(number!)") 
} else {
    print("字符串转换整数失败") 
}

// 字符串转换整数成功:123

可选项绑定

if let number = Int("123") {
   print("字符串转换整数成功:\(number)") 
    // number是强制解包之后的Int值
    // number作用域仅限于这个大括号
} else { 
    print("字符串转换整数失败")
}


// 字符串转换整数成功:123

eg:

enum Season : Int {
    case spring = 1, summer, autumn, winter
}
if let season = Season(rawValue: 6) {
    switch season { 
        case .spring:
            print("the season is spring")
        default:
            print("the season is other")
    }
} else {
    print("no such season")
}


// no such season

等价写法

可选项绑定中,如果多个条件比如下面


 if let first = Int("4") {
    if let second = Int("42") {
        if first < second && second < 100 {
            print("\(first) < \(second) < 100")
            } 
        }
}
// 4 < 42 < 100

可以用 , 分割开,看起来更简单

 if let first = Int("4"),
    let second = Int("42"),
    first < second && second < 100 {
    print("\(second) < \(second) < 100")
}
// 4 < 42 < 100

while循环中使用可选项绑定

//遍历数组,将遇到的正数都加起来,如果遇到负数或者非数字,停止遍历
// var strs = ["10", "20", "abc", "-20", "30"]

var index = 0
var sum = 0
while let num = Int(strs[index]), num > 0 {
    sum += num
    index += 1 
}
    
print(sum)

空合并运算符 ??(Nil-Coalescing Operator)

eg:


public func ?? <T>(optional: T?, defaultValue: @autoclosure () throws -> T?) rethrows -> T?
public func ?? <T>(optional: T?, defaultValue: @autoclosure () throws -> T) rethrows -> T

规律: 返回的类型取决于b

举例如下:

let a: Int? = 1
let b: Int? = 2
let c = a ?? b // c是Int? , Optional(1)

let a: Int? = 1
let b: Int = 2
let c = a ?? b // c是Int , 1

let a: Int? = nil
let b: Int = 2
let c = a ?? b // c是Int , 2

let a: Int? = nil
let b: Int? = 2
let c = a ?? b // c是Int? , Optional(2)

let a: Int? = nil 
let b: Int = 2
// 如果不使用??运算符 
let c: Int
if let tmp = a {
    c = tmp
} else { 
    c=b
}

// 使用 ?? 运算符
let c = a ?? b // c是Int? , nil

多个 ?? 一起使用


let a: Int? = 1
let b: Int? = 2
let c = a ?? b ?? 3 // c是Int , 1
let a: Int? = nil
let b: Int? = 2
let c = a ?? b ?? 3 // c是Int , 2
let a: Int? = nil
let b: Int? = nil
let c = a ?? b ?? 3 // c是Int , 3

??跟if let配合使用


let a: Int? = nil
let b: Int? = 2
if let c = a ?? b {
    print(c) 
}
// 类似于if a != nil || b != nil

if let c = a, let d = b {
    print(c)
    print(d) 
}
// 类似于if a != nil && b != nil

guard语句


guard 条件 else {
// do something....
退出当前作用域
// return、break、continue、throw error }

假设我们有个登陆的需求,要求输入账号,密码。缺一不可。

用if语句书写

//if语句实现登陆
func login(_ info: [String : String]) { 
    let username: String
    if let tmp = info["username"] {
        username = tmp
    } else {
        print("请输入用户名")
        return
    }
    
    let password: String
    if let tmp = info["password"] {
        password = tmp
    } else {
        print("请输入密码")
        return
    }
    
    // 能来到这里,说明,username和password都是有值的
    // if username ....
    // if password ....
    print("用户名:\(username)", "密码:\(password)", "登陆ing")
}
 
// 调用
login(["username" : "jack", "password" : "123456"]) // 用户名:jack 密码:123456 登陆ing 

login(["password" : "123456"]) // 请输入密码

login(["username" : "jack"]) // 请输入用户名

如果用guard来书写


func login(_ info: [String : String]) {
    guard let username = info["username"] else {
            print("请输入用户名")
            return
    }
    
    guard let password = info["password"] else {
            print("请输入密码")
            return
    }
    
    // if username ....
    // if password ....
    print("用户名:\(username)", "密码:\(password)", "登陆ing")
}

隐式解包(Implicitly Unwrapped Optional)


let num1: Int! = 10
let num2: Int = num1
if num1 != nil {
    print(num1 + 6) // 16
}
if let num3 = num1 {
    print(num3) //10
}

注意不能设置为nil

let num1: Int! = nil
// Fatal error: Unexpectedly found nil while implicitly unwrapping an Optional value
let num2: Int = num1

尽量不要使用这个强制解包。
除非你设计接口,不希望接收空值,如果别人传Nil过来,直接报错

字符串插值


var age: Int? = 10
print("My age is \(age)")
 print("My age is \(age!)")
// My age is 10

 print("My age is \(String(describing: age))")
// My age is Optional(10)

 print("My age is \(age ?? 0)")
// My age is 10

多重可选项

var num1: Int? = 10
var num2: Int?? = num1
var num3: Int?? = 10


print(num2 == num3) // true

还有下面这种

var num1: Int? = nil
var num2: Int?? = num1
var num3: Int?? = nil


print(num2 == num3) // false
(num2 ?? 1) ?? 2 // 2
(num3 ?? 1) ?? 2 // 1

参考资料:

Swift官方源码

从入门到精通Swift编程

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