Java Stream流操作
2020-07-16 本文已影响0人
xiaogp
Java流操作概览
在处理集合时如果需要遍历元素, 并且对每一个元素进行某项操作, 就可以使用Java的流操作
(1) 流操作不更改原始集合, 会生成一个新的集合
(2) 流操作是懒惰执行的, 直到需要拿到执行结果的时候才会执行
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
public class streamTest {
public static void main(String[] args) {
// filter
// Arrays
String[] a = {"a", "bb", "ccc", "dd"};
long aCount = Arrays.stream(a).filter(x -> x.length() >= 2).count();
System.out.println(aCount);
List<String> aa = Arrays.stream(a).filter(x -> x.length() >= 2).collect(Collectors.toList());
System.out.println(aa);
// ArrayList
ArrayList<String> b = new ArrayList<>(Arrays.asList("a", "bb", "ccc", "dd"));
long bCount = b.stream().filter(x -> x.length() >= 2).count();
System.out.println(bCount);
List<String> bb = b.stream().filter(x -> x.length() >= 2).collect(Collectors.toList());
System.out.println(bb);
// 使用parallelStream可以并行
List<String> bbb = b.parallelStream().filter(x -> x.length() >= 2).collect(Collectors.toList());
System.out.println(bbb);
}
}
Java流的创建
Collection有stream接口直接创建流, 数组可以通过stream.of静态方法, 或者Arrays.stream可以指定数组的开始和结束位置
// 几种创建流的方式
// 数组
Stream<Integer> aStream = Stream.of(1, 2, 3, 4, 5);
List<Integer> aList = aStream.filter(x -> x > 3).collect(Collectors.toList());
System.out.println(aList); // [4, 5]
Stream<String> bStream = Stream.of("1,2,3,4,5".split(","));
List<Integer> bList = bStream.map(x -> Integer.valueOf(x)).filter(x -> x >3).collect(Collectors.toList());
System.out.println(bList); // [4, 5]
Stream<String> cStream = Arrays.stream("1,2,3,4,5".split(","));
List<Integer> cList = cStream.map(x -> Integer.valueOf(x)).filter(x -> x >3).collect(Collectors.toList());
System.out.println(cList); // [4, 5]
// 指定数组的开始结束索引位置
Integer[] tmpArray = {1, 2 ,3 ,4, 5};
Stream<Integer> dStream = Arrays.stream(tmpArray, 1, 3);
dStream.forEach(x -> System.out.println(x)); // 2, 3
// 集合Collection
Stream<Integer> eStream = Arrays.asList(1, 2, 3, 4, 5).stream();
List<Integer> eList = eStream.filter(x -> x > 3).collect(Collectors.toList());
System.out.println(eList); // [4, 5]
转换操作 filter, map, flatMap
流的转换会产生一个新的流, 转换操作需要指定转换函数, 可以使用lambda表达式或者方法引用::
// map
// lambda表达式
List<Integer> fList = Arrays.asList(1, 2, 3, 4, 5).stream().map(x -> x + 1).collect(Collectors.toList());
System.out.println(fList);
// 方法引用::
List<Integer> gList = Arrays.asList(1, 2, 3, 4, 5).stream().map(streamTest::inc1).collect(Collectors.toList());
System.out.println(gList);
private static Integer inc1(Integer value) {
return value + 1;
}
抽取子流 limit和skip
// 抽取子流 limit skip
List<Integer> iList = Arrays.asList(1, 2, 3, 4, 5);
iList.stream().limit(3).forEach(x -> System.out.print(x)); // 123
System.out.println();
iList.stream().skip(1).forEach(x -> System.out.print(x)); // 2345
获取无限流
// 获取无限流
Stream<Integer> jStream = Stream.generate(() -> 1); // 生成全是1的无限流
// jStream.forEach(x -> System.out.println(x));
Stream<Double> kStream = Stream.generate(Math::random).limit(10); // 生成10个[0,1)之间的随机小数
kStream.forEach(x -> System.out.println(x));
排序
// 排序
List<Integer> lList = Arrays.asList(1, 3, 5, 2, 4);
List<Integer> mList = lList.stream().sorted().collect(Collectors.toList());
System.out.println(mList); // [1, 2, 3, 4, 5]
List<Integer> nList = lList.stream().sorted(Comparator.reverseOrder()).collect(Collectors.toList());
System.out.println(nList); // [5, 4, 3, 2, 1]
收集结果
可以将流操作之后的结果收集为ArrayList
,HashSet
,HashMap
,String
。
Stream<String> stream = Stream.of("2", "2", "3");
List<String> list = stream.map(s -> s + "_").collect(Collectors.toList());
Set<String> set = stream.map(s -> s + s).collect(Collectors.toSet());
Map<String, String> map = stream.map(s -> s + s).collect(Collectors.toMap(k -> k, v -> v + "_", (o, n) -> n));
String string = stream.collect(Collectors.joining(",")); // 2,2,3
在sql语句in条件查询使用stream收集为,分割字符串:
conn = connPool.getConnection();
stmt = conn.createStatement();
String param = myCollections.stream().map(s -> "\"" + s + "\"").collect(Collectors.joining(","));
ResultSet rs = stmt.executeQuery(String.format("select feature2 from table where feature1 in (%s) and status='Y'", param));
while (rs.next()) {
// TODO
}
Collectors.toMap
第一个参数是获得key
,第二个参数是获得value
,第三个参数是解决key冲突
的处理方式
public static void streamToMao() {
List<String> a = new ArrayList<>(Arrays.asList("a", "b", "c", "d"));
Map<String, String> b = a.stream().collect(Collectors.toMap(s -> s, s -> s, (o, n) -> n));
Map<String, String> c = a.stream().collect(Collectors.toMap(s -> s + "_" + s, s -> s, (o, n) -> n));
// 方法引用
Map<String, String> d = a.stream().collect(Collectors.toMap(test2::getString, v -> v, (o, n) -> n));;
// 等同于
Map<String, String> e = new HashMap<>();
for (String item: a) {
e.put(item + "_" + item, item);
}
}
使用基本类型流
使用包装器Stream<>是低效的, 流库有专门的类型IntStream, LongStream, DoubleStream, 无需使用包装器
// 使用基本类型流
IntStream intStream1 = IntStream.of(1, 2, 3, 4, 5);
intStream1.forEach(System.out::print);
DoubleStream doubleStream1 = DoubleStream.of(1.0, 2.0, 3.0);
doubleStream1.forEach(System.out::print);
多维数组的流操作
// 多维数组
Integer[][] multiArray = {{1, 2, 3}, {2, 3, 4}};
Stream<Integer[]> multiStream = Stream.of(multiArray);
// multiStream.forEach(x -> System.out.println(Arrays.toString(x)));
// 每个元素求长度
// List<Integer> xLength = multiStream.map(x -> x.length).collect(Collectors.toList());
// System.out.println(xLength); // [3, 3]
// 每个元素求最大
List<Integer> xMax = multiStream.map(x -> Collections.max(Arrays.asList(x))).collect(Collectors.toList());
System.out.println(xMax); // [3, 4]