django的Form三
2017-07-25 本文已影响0人
赖三石
常用选择插件
# 单radio,值为字符串
# user = fields.CharField(
# initial=2,
# widget=widgets.RadioSelect(choices=((1,'上海'),(2,'北京'),))
# )
# 单radio,值为字符串
# user = fields.ChoiceField(
# choices=((1, '上海'), (2, '北京'),),
# initial=2,
# widget=widgets.RadioSelect
# )
# 单select,值为字符串
# user = fields.CharField(
# initial=2,
# widget=widgets.Select(choices=((1,'上海'),(2,'北京'),))
# )
# 单select,值为字符串
# user = fields.ChoiceField(
# choices=((1, '上海'), (2, '北京'),),
# initial=2,
# widget=widgets.Select
# )
# 多选select,值为列表
# user = fields.MultipleChoiceField(
# choices=((1,'上海'),(2,'北京'),),
# initial=[1,],
# widget=widgets.SelectMultiple
# )
# 单checkbox
# user = fields.CharField(
# widget=widgets.CheckboxInput()
# )
# 多选checkbox,值为列表
# user = fields.MultipleChoiceField(
# initial=[2, ],
# choices=((1, '上海'), (2, '北京'),),
# widget=widgets.CheckboxSelectMultiple
# )
在使用选择标签时,需要注意choices的选项可以从数据库中获取,但是由于是静态字段 获取的值无法实时更新,那么需要自定义构造方法从而达到此目的。
models.py
class UserType(models.Model):
caption = models.CharField(max_length=32)
class UserInfo(models.Model):
username = models.CharField(max_length=32)
email = models.EmailField()
user_type = models.ForeignKey(to='UserType',to_field='id')
方式一:
from django.forms import Form
from django.forms import widgets
from django.forms import fields
class UserInfoForm(forms.Form):
username = Ffields.CharField(max_length=32)
email = Ffields.EmailField()
user_type = Ffields.ChoiceField(
choices=models.UserType.objects.values_list('id','caption')
)
def __init__(self, *args, **kwargs):
super(UserInfoForm,self).__init__(*args, **kwargs)
self.fields['user_type'].choices = models.UserType.objects.values_list('id','caption')
方式二:
使用django提供的ModelChoiceField和ModelMultipleChoiceField字段来实现
from django import forms
from django.forms import fields
from django.forms import widgets
from django.forms import models as form_model #这里models重复,注意
class FInfo(forms.Form):
authors = form_model.ModelMultipleChoiceField(queryset=models.NNewType.objects.all())
# authors = form_model.ModelChoiceField(queryset=models.NNewType.objects.all())