Sturts的简单搭建
2018-04-25 本文已影响0人
阿狸演绎
Struts的简单搭建
struts2
搭建
1 web.xml
[核心过滤器]
/* 过滤所有
<filter-class> StrutsPrepare
①纯手打
source
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="[http://www.w3.org/2001/XMLSchema-instance](http://www.w3.org/2001/XMLSchema-instance)" xmlns="[http://xmlns.jcp.org/xml/ns/javaee](http://xmlns.jcp.org/xml/ns/javaee)" xsi:schemaLocation="[http://xmlns.jcp.org/xml/ns/javaee](http://xmlns.jcp.org/xml/ns/javaee)[http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd](http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd)" id="WebApp_ID" version="3.1">
<display-name>Struts01</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<!-- -->
<filter>
<filter-name>struts</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
②Design Filters
image.png
2.Action
package com.xxh.entity;
public class LoginAction {
private Integer password;
private String userName;
public String execute(){
System.out.println("userName"+userName+"password"+password);
return "success";
}
public Integer getPassword() {
return password;
}
public void setPassword(Integer password) {
this.password = password;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
}
3.dtd 约束文件
struts.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"[http://struts.apache.org/dtds/struts-2.3.dtd](http://struts.apache.org/dtds/struts-2.3.dtd)">
<struts>
<!--注册包 包的名字可以随便取-->
<package name="xxx" namespace="/" extends="struts-default">
<!-- 注册类 name是前台需要传参的地址 class是Action的全类目,方便能找到Action-->
<action name="login" class="com.xxh.entity.LoginAction">
<result name="success">/success.jsp</result>
</action>
</package>
</struts>
容易出错的地方
HTTP Status 404 - There is no Action mapped for namespace [/] and action name [login] associated with context path
struts.xml 在必须在src下,或者在namespace下修改路径,默认的struts.xml在src下
4.在WebRoot下的WEB-INF中的index.jsp
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
</head>
<body>
<form action="login" method="post">
用户名：<input type="text" name="username"><br>
密 码：<input type="password" name="password"><br>
<input type="submit" value="登录">
</form>
</body>
</html>
创建一个登陆成功的界面
<%@ page language="java" import="java.util.*"
pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<html>
<head>
</head>
<body>
欢迎您：${username}
</body>
</html>
注意事项
1web.xml中过滤器的名称可以随便起
2LoginAction notfound
struts.xml中的全类名写错了
3LoginAction 中的execute(),他是struts的默认的执行方法
4.配置文件名称必须是struts.xml,全小写
报404错:There is no Action mapped
5如果修改tomact默认的shutdown端口,服务器不能正常启动
6.web.xml核心过滤器必须有
执行流程
index.jsp--->请求[先找核心过滤器(web.xml)]---->映射到struts.xml文件---->实体类[login,返回值success]---->execute方法返回success---->success.jsp页面[el输出]
前后台传参;
前台属性的值
后台:封装成对象中的属性进行接收
//代码流程:
1:导包
2:配置web.xml
3:新建实体类
4:新建struts.xml
5:index
6:输出 success
