Maximum Submatrix
2018-06-28 本文已影响10人
Frank_Kivi
https://www.lintcode.com/problem/maximum-submatrix/description
public class Solution {
/**
* @param matrix: the given matrix
* @return: the largest possible sum
*/
public int maxSubmatrix(int[][] matrix) {
// write your code here
if (matrix.length == 0 || matrix[0].length == 0) {
return 0;
}
int[][] sumMatrix = new int[matrix.length + 1][matrix[0].length];
for (int i = 0; i < matrix.length; i++) {
int[] ints = matrix[i];
for (int j = 0; j < ints.length; j++) {
int anInt = ints[j];
sumMatrix[i + 1][j] = sumMatrix[i][j] + anInt;
}
}
int result = Integer.MIN_VALUE;
for (int top = 1; top < sumMatrix.length; top++) {
for (int bottom = top; bottom < sumMatrix.length; bottom++) {
int[] compression = getCompression(sumMatrix, top, bottom);
result = Math.max(result, getMax(compression));
}
}
return result;
}
private int getMax(int[] compression) {
int min = 0;
int max = Integer.MIN_VALUE;
int sum = 0;
for (int i = 0; i < compression.length; i++) {
int i1 = compression[i];
sum += i1;
min = Math.min(sum, min);
max = Math.max(max, sum - min);
}
return max;
}
private int[] getCompression(int[][] sumMatrix, int top, int bottom) {
int[] dp = new int[sumMatrix[0].length];
for (int i = 0; i < dp.length; i++) {
dp[i] = sumMatrix[bottom][i] - sumMatrix[top - 1][i];
}
return dp;
}
}