计算两条线段的交点
2020-07-23 本文已影响0人
宿州刘德华
//线段平行或者不相交返回false 否则返回交点坐标
getPolyLinesIntersection(line1, line2) {
//a b 代表线段1的两个端点 c d 代表线段2的两个端点
let a = {
x: line1[0][0], y: line1[0][1],
}, b = {
x: line1[1][0], y: line1[1][1],
}, c = {
x: line2[0][0], y: line2[0][1],
}, d = {
x: line2[1][0], y: line2[1][1],
};
/** 1 解线性方程组, 求线段交点. **/
// 如果分母为0 则平行或共线, 不相交
let denominator = (b.y - a.y) * (d.x - c.x) - (a.x - b.x) * (c.y - d.y);
if (denominator === 0) {
return false;
}
// 线段所在直线的交点坐标 (x , y)
let x = ((b.x - a.x) * (d.x - c.x) * (c.y - a.y)
+ (b.y - a.y) * (d.x - c.x) * a.x
- (d.y - c.y) * (b.x - a.x) * c.x) / denominator;
let y = -((b.y - a.y) * (d.y - c.y) * (c.x - a.x)
+ (b.x - a.x) * (d.y - c.y) * a.y
- (d.x - c.x) * (b.y - a.y) * c.y) / denominator;
/** 2 判断交点是否在两条线段上 **/
if (
// 交点在线段1上
(x - a.x) * (x - b.x) <= 0 && (y - a.y) * (y - b.y) <= 0
// 且交点也在线段2上
&& (x - c.x) * (x - d.x) <= 0 && (y - c.y) * (y - d.y) <= 0
) {
// 返回交点p
return {
x: x,
y: y
}
}
//否则不相交
return false
},