Python遍历列表时并删除其中符合条件的元素

1.内建filter函数

a = [1,2,3,4,5,6,7,8]
b = filter(lambda x: x>2,a)

2.列表推导式

a = [1,2,3,4,5,6,7,8]
b = [i for i in a if i >2]

其实1与2是等价的
详见：https://docs.python.org/3/library/functions.html#filter