Palindrome Number
2017-12-20 本文已影响0人
无云清晨
判断整数是否是回文
bool isPalindrome(int x) {
if(x < 0)
{
return false;
}
int t = x / 10;
int length= 1;
while(t)
{
length = length * 10;
t = t / 10;
}
int left;
int right;
int r = x;
while(x)
{
left = r / length;
right = x % 10;
if(left != right)
{
return false;
}
r = r % length;
length = length / 10;
x = x/10;
}
return true;
}