算法2
2019-05-18 本文已影响0人
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int countRange(const int *numbers, int length, int start, int end) {
if (numbers == nil) { return 0; }
int count = 0;
for (int i = 0; i < length; i ++) {
if (numbers[i] >= start && numbers[i] <= end) {
count++;
}
}
return count;
}
int getDuplication(const int *numbers,int length) {
if (numbers == nil || length <= 0) { return -1;}
int start = 1;
int end = length - 1;
while (end >= start) {
int middle = ((end - start) >> 1) + start;
int count = countRange(numbers, length, start, middle);
if (end == start) { //已经遍历完
if (count > 1) {
return start;
} else {
break;
}
}
if (count >(middle - start + 1)) {
end = middle;
} else {
start = middle + 1;
}
}
return -1;
}