Max Product Of Cutting Rope
2018-05-24 本文已影响0人
GakkiLove
Given a rope with positive integer-length n, how to cut the rope into m integer-length parts with length p[0], p[1], ...,p[m-1], in order to get the maximal product of p[0]p[1] ... p[m-1]? m is determined by you and must be greater than 0 (at least one cut must be made). Return the max product you can have.
Assumptions
n >= 2
Examples
n = 12, the max product is 3 3 3 3 = 81(cut the rope into 4 pieces with length of each is 3).
class Solution(object):
def maxProduct(self, length):
if length == 2:
return 1
max_val = 0
for i in xrange(1,length-1):
max_val = max(max_val,max(i * (length - i),self.maxProduct(length - i) * i))
return max_val