莫烦强化学习笔记2- Q Learning
2019-02-11 本文已影响0人
Tutan_dcb0
Q-learning 决策: 根据Q表,选择reward较大的action.
Q-learning 更新:
这一张图概括了我们之前所有的内容. 这也是 Q learning 的算法, 每次更新我们都用到了 Q 现实和 Q 估计, 而且 Q learning 的迷人之处就是 在 Q(s1, a2) 现实 中, 也包含了一个 Q(s2) 的最大估计值, 将对下一步的衰减的最大估计和当前所得到的奖励当成这一步的现实, 很奇妙吧. 最后我们来说说这套算法中一些参数的意义. Epsilon greedy 是用在决策上的一种策略, 比如 epsilon = 0.9 时, 就说明有90% 的情况我会按照 Q 表的最优值选择行为, 10% 的时间使用随机选行为. alpha是学习率, 来决定这次的误差有多少是要被学习的, alpha是一个小于1 的数. gamma 是对未来 reward 的衰减值. 我们可以这样想象.
代码如下
"""
A simple example for Reinforcement Learning using table lookup Q-learning method.
An agent "o" is on the left of a 1 dimensional world, the treasure is on the rightmost location.
Run this program and to see how the agent will improve its strategy of finding the treasure.
View more on my tutorial page: https://morvanzhou.github.io/tutorials/
"""
import numpy as np
import pandas as pd
import time
np.random.seed(2) # reproducible
N_STATES = 6 # the length of the 1 dimensional world
ACTIONS = ['left', 'right'] # available actions
EPSILON = 0.9 # greedy police
ALPHA = 0.1 # learning rate
GAMMA = 0.9 # discount factor
MAX_EPISODES = 13 # maximum episodes
FRESH_TIME = 0.3 # fresh time for one move
def build_q_table(n_states, actions):
table = pd.DataFrame(
np.zeros((n_states, len(actions))), # q_table initial values
columns=actions, # actions's name
)
# print(table) # show table
return table
def choose_action(state, q_table):
# This is how to choose an action
state_actions = q_table.iloc[state, :]
if (np.random.uniform() > EPSILON) or ((state_actions == 0).all()): # act non-greedy or state-action have no value
action_name = np.random.choice(ACTIONS)
else: # act greedy
action_name = state_actions.idxmax() # replace argmax to idxmax as argmax means a different function in newer version of pandas
return action_name
def get_env_feedback(S, A):
# This is how agent will interact with the environment
if A == 'right': # move right
if S == N_STATES - 2: # terminate
S_ = 'terminal'
R = 1
else:
S_ = S + 1
R = 0
else: # move left
R = 0
if S == 0:
S_ = S # reach the wall
else:
S_ = S - 1
return S_, R
def update_env(S, episode, step_counter):
# This is how environment be updated
env_list = ['-']*(N_STATES-1) + ['T'] # '---------T' our environment
if S == 'terminal':
interaction = 'Episode %s: total_steps = %s' % (episode+1, step_counter)
print('\r{}'.format(interaction), end='')
time.sleep(2)
print('\r ', end='')
else:
env_list[S] = 'o'
interaction = ''.join(env_list)
print('\r{}'.format(interaction), end='')
time.sleep(FRESH_TIME)
def rl():
# main part of RL loop
q_table = build_q_table(N_STATES, ACTIONS)
for episode in range(MAX_EPISODES):
step_counter = 0
S = 0
is_terminated = False
update_env(S, episode, step_counter)
while not is_terminated:
A = choose_action(S, q_table)
S_, R = get_env_feedback(S, A) # take action & get next state and reward
q_predict = q_table.loc[S, A]
if S_ != 'terminal':
q_target = R + GAMMA * q_table.iloc[S_, :].max() # next state is not terminal
else:
q_target = R # next state is terminal
is_terminated = True # terminate this episode
q_table.loc[S, A] += ALPHA * (q_target - q_predict) # update
S = S_ # move to next state
update_env(S, episode, step_counter+1)
step_counter += 1
return q_table
if __name__ == "__main__":
q_table = rl()
print('\r\nQ-table:\n')
print(q_table)