leetcode2-Add Two Numbers

问题：

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example:

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.

解法：

public class Solution {
    public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
        ListNode ln1 = l1, ln2 = l2, head = null, node = null;
        int carry = 0, remainder = 0, sum = 0;
        head = node = new ListNode(0);
        
        while(ln1 != null || ln2 != null || carry != 0) {
            sum = (ln1 != null ? ln1.val : 0) + (ln2 != null ? ln2.val : 0) + carry;
            carry = sum / 10;
            remainder = sum % 10;
            node = node.next = new ListNode(remainder);
            ln1 = (ln1 != null ? ln1.next : null);
            ln2 = (ln2 != null ? ln2.next : null);
        }
        return head.next;
    }
}