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iOS 写一个自带复制功能的Label

2015-03-23  本文已影响9863人  Stark_Dylan

在iOS8 之后, 我们发现UILabel不在为我们提供长按弹出复制等操作了, 我们来继承UILabel自己写一个带复制功能的按钮

//
//  XLabel.m
//  SuperMan
//
//  Created by XueYulun on 15/3/23.
//  Copyright (c) 2015年 X. All rights reserved.
//

#import "XLabel.h"

@implementation XLabel

-(BOOL)canBecomeFirstResponder {
    
    return YES;
}

// 可以响应的方法
-(BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    
    return (action == @selector(copy:));
}

//针对于响应方法的实现
-(void)copy:(id)sender {
    
    UIPasteboard *pboard = [UIPasteboard generalPasteboard];
    pboard.string = self.text;
}

//UILabel默认是不接收事件的,我们需要自己添加touch事件
-(void)attachTapHandler {
    
    self.userInteractionEnabled = YES;
    UILongPressGestureRecognizer *touch = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleTap:)];
    [self addGestureRecognizer:touch];
}

//绑定事件
- (id)initWithFrame:(CGRect)frame {
    self = [super initWithFrame:frame];
    if (self) {
        
        [self attachTapHandler];
    }
    return self;
}

-(void)awakeFromNib {
    
    [super awakeFromNib];
    [self attachTapHandler];
}

-(void)handleTap:(UIGestureRecognizer*) recognizer {
    
    [self becomeFirstResponder];
    UIMenuItem *copyLink = [[UIMenuItem alloc] initWithTitle:@"复制"
                                                      action:@selector(copy:)];
    [[UIMenuController sharedMenuController] setMenuItems:[NSArray arrayWithObjects:copyLink, nil]];
    [[UIMenuController sharedMenuController] setTargetRect:self.frame inView:self.superview];
    [[UIMenuController sharedMenuController] setMenuVisible:YES animated: YES];
}

@end

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