13. 罗马数字转整数
2019-04-27 本文已影响0人
王王韦王奇
class Solution:
def romanToInt(self, s: str) -> int:
num = 0
change = {"I": 1, "V": 5, "X": 10, "L": 50, "C": 100, "D": 500, "M": 1000,
"IV": 4, "IX": 9, "XL": 40, "XC": 90, "CD": 400, "CM": 900}
i = 0
while i < len(s):
if i + 1 <= len(s) - 1:
if s[i: i + 2] in change:
num += change[s[i: i+2]]
i += 2
continue
num += change[s[i]]
i += 1
return num