Django 自定义管理员的 User 页面

Django 2.1

自定义User 列表页面 的显示项目

1. 进入某个App的 admin.py， 我选自己建的Accounts App， 我在这里建立了 UserProfile model
2. 编辑

from django.contrib import admin
 # 1. 导入默认UserAdmin 作为Base Class
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from django.contrib.auth.models import User

# 2.  Define a new User admin
class UserAdmin(BaseUserAdmin):
    # 3. 重新定义 list_display
    list_display = ('username', 'email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff') 

# 4. 注销 User
admin.site.unregister(User)
# 5. 重新注册 User
admin.site.register(User, UserAdmin)

为 User 详情页面添加 Profile 信息

1. 在上一步基础上，导入自己的Profile model
2. 定义 Inline Class
3. 在自定义的UserAdmin中加入Inline信息
   完整代码如下：

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from django.contrib.auth.models import User
from accounts.models import UserProfile


class UserProfileAdmin(admin.ModelAdmin):
    list_display = ['user', 'phone_number', 'gender', 'date_of_birth', 'address', 'suburb', 'city', 'post_code']


# Define an inline admin descriptor for Employee model
# which acts a bit like a singleton
class EmployeeInline(admin.StackedInline):
    model = UserProfile
    can_delete = False
    verbose_name_plural = 'profile'


# Define a new User admin
class UserAdmin(BaseUserAdmin):
    list_display = ('username', 'email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff')
    inlines = (EmployeeInline,)


# Re-register UserAdmin
admin.site.unregister(User)
admin.site.register(User, UserAdmin)
admin.site.register(UserProfile, UserProfileAdmin)