django分页三
2017-07-18 本文已影响0人
赖三石
urls.py同前
views.py
# encoding=utf-8
from django.shortcuts import render
# Create your views here.
def index(request):
#模拟数据,列表生成式
a_list = [i for i in range(1, 1003)]
#获取当前页, 注意获取时是字符串，要转换为int
current_page = request.GET.get('p', 1)
current_page = int(current_page)
#数据切片
#data = a_list[:10]
#data = a_list[20: 30]
#每页显示10条数据,并且得与current_page发生关系
start = (current_page-1) * 10
end = current_page * 10
data = a_list[start: end]
########页码########
#total_count:数据总条数
#page_num:总页数
total_count = len(a_list)
page_num, y = divmod(total_count, 10)
#y为余数，y=0为假
if y:
page_num += 1
############################################################
# start_index = 1
# end_index = page_num + 1
# start_index = current_page - 5
# end_index = current_page + 5 + 1
#解决页码变为负数问题
if page_num <= 6:
start_index = 1
end_index = page_num + 1
else:
if current_page - 5 <= 0:
start_index = 1
end_index = current_page + 5 + 1
else:
if current_page + 5 + 1 > page_num:
end_index = page_num + 1
start_index = page_num - 10
else:
start_index = current_page - 5
end_index = current_page + 5 + 1
#############################################################
#页码的前端显示
page_html_list = []
if current_page == 1:
prev = '<a href="#">上一页</a>'
else:
prev = '<a href="/index/?p=%s">上一页</a>' % (current_page-1)
page_html_list.append(prev)
for j in range(start_index, end_index):
if current_page == j:
page_html = '<a class="active" href="/index/?p=%s">%s</a>' % (j, j)
else:
page_html = '<a href="/index/?p=%s">%s</a>' % (j, j)
page_html_list.append(page_html)
if current_page == page_num:
nex = '<a href="#">下一页</a>'
else:
nex = '<a href="/index/?p=%s">下一页</a>' % (current_page+1)
page_html_list.append(nex)
return render(request, 'index.html', {'data': data, 'page': page_html_list})
template
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
<style>
.active{
background-color: #1b6d85;
}
</style>
</head>
<body>
<ul>
{% for d in data %}
<li>{{ d }}</li>
{% endfor %}
</ul>
{% for i in page %}
{{ i|safe }}
{% endfor %}
</body>
</html>
views.py
提取 每页要显示数据数量 与 页码显示条数
# encoding=utf-8
from django.shortcuts import render
# Create your views here.
def index(request):
#每页数据数量
per_page_count = 8
#显示页码数
view_page = 9
#模拟数据,列表生成式
a_list = [i for i in range(1, 1003)]
#获取当前页, 注意获取时是字符串，要转换为int
current_page = request.GET.get('p', 1)
current_page = int(current_page)
#数据切片
#data = a_list[:10]
#data = a_list[20: 30]
#每页显示10条数据,并且得与current_page发生关系
start = (current_page-1) * per_page_count
end = current_page * per_page_count
data = a_list[start: end]
########页码########
#total_count:数据总条数
#page_num:总页数
total_count = len(a_list)
page_num, y = divmod(total_count, per_page_count)
#y为余数，y=0为假
if y:
page_num += 1
############################################################
# start_index = 1
# end_index = page_num + 1
# start_index = current_page - 5
# end_index = current_page + 5 + 1
#解决页面变为负数问题
if page_num <= (view_page+1)/2:
start_index = 1
end_index = page_num + 1
else:
if current_page - (view_page-1)/2 <= 0:
start_index = 1
end_index = current_page + (view_page-1)/2 + 1
else:
if current_page + (view_page-1)/2 + 1 > page_num:
end_index = page_num + 1
start_index = page_num - view_page + 1
else:
start_index = current_page - (view_page-1)/2
end_index = current_page + (view_page-1)/2 + 1
################################################################
page_html_list = []
if current_page == 1:
prev = '<a href="#">上一页</a>'
else:
prev = '<a href="/index/?p=%s">上一页</a>' % (current_page-1)
page_html_list.append(prev)
for j in range(start_index, end_index):
if current_page == j:
page_html = '<a class="active" href="/index/?p=%s">%s</a>' % (j, j)
else:
page_html = '<a href="/index/?p=%s">%s</a>' % (j, j)
page_html_list.append(page_html)
if current_page == page_num:
nex = '<a href="#">下一页</a>'
else:
nex = '<a href="/index/?p=%s">下一页</a>' % (current_page+1)
page_html_list.append(nex)
return render(request, 'index.html', {'data': data, 'page': page_html_list})
