leetcode

138. Copy List with Random Point

2020-02-26  本文已影响0人  十月里的男艺术家

题目:

138. Copy List with Random Pointer

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.

Return a deep copy of the list.

The Linked List is represented in the input/output as a list of n nodes. Each node is represented as a pair of [val, random_index] where:

Example 1:

Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]

Example 2:

Input: head = [[1,1],[2,1]]
Output: [[1,1],[2,1]]

Example 3:

Input: head = [[3,null],[3,0],[3,null]]
Output: [[3,null],[3,0],[3,null]]

Example 4:

Input: head = []
Output: []
Explanation: Given linked list is empty (null pointer), so return null.

Constraints:

138. 复制带随机指针的链表

给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点。

要求返回这个链表的 深拷贝。

我们用一个由 n 个节点组成的链表来表示输入/输出中的链表。每个节点用一个 [val, random_index] 表示:

示例 1:

输入:head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
输出:[[7,null],[13,0],[11,4],[10,2],[1,0]]

示例 2:

输入:head = [[1,1],[2,1]]
输出:[[1,1],[2,1]]

示例 3:

输入:head = [[3,null],[3,0],[3,null]]
输出:[[3,null],[3,0],[3,null]]

示例 4:

输入:head = []
输出:[]
解释:给定的链表为空(空指针),因此返回 null。

提示:

思路:

方法1:

Hashmap字典映射

方法2:

  1. 新节点连接到原始节点(node1->node1'->node2->node2')
  2. 新节点random指针赋值
  3. 拆分新旧链表

代码:

class Solution:
    def copyRandomList(self, head: Node) -> Node:
        from collections import defaultdict
        d = defaultdict(lambda: Node(0))
        d[None] = None
        current = head
        while current:
            d[current].val = current.val
            d[current].next = d[current.next]
            d[current].random = d[current.random]
            current = current.next
        return d[head]

    def copyRandomListV01(self, head: Node) -> Node:
        d = {}
        current = head
        while current:
            d[current] = Node(current.val)
            current = current.next

        current = head

        while current:
            d[current].next = d.get(current.next, None)
            d[current].random = d.get(current.random, None)
            current = current.next

        return d[head]

    def copyRandomListV02(self, head: Node) -> Node:
        current = head
        while current:
            node = Node(current.val)
            node.next = current.next
            current.next = node
            current = node.next

        current = head
        while current:
            current.next.random = current.random and current.random.next
            current = current.next.next

        second = head.next
        current = head.next
        while current.next:
            head.next = current.next
            head = current.next
            current.next = head.next
            current = current.next
        head.next = None
        return second
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