2017-09-24
2017-09-24 本文已影响0人
Rene2
# \frac{1}{\pi}=\frac{2\sqrt{2}}{9801}\sum_{k=0}^\infty\frac{(4k)!(1103+26390k)}{(k!)^4396^{4k}}
- hsjxj
- kkskxkx
2017-09-24
2017-09-24
2017-09-24
# \frac{1}{\pi}=\frac{2\sqrt{2}}{9801}\sum_{k=0}^\infty\frac{(4k)!(1103+26390k)}{(k!)^4396^{4k}}
- hsjxj
- kkskxkx
2017-09-24
