Leetcode Diary
2016-12-08 本文已影响3人
VincentJianshu
DP Section
64_Minimum_Path_Sum
Simple DP
public class Solution {
public int minPathSum(int[][] grid) {
int row = grid.length;
int col = grid[0].length;
for (int i = 0; i < row - 1; i++) {
grid[i+1][0] += grid[i][0];
}
for (int i = 0; i < col - 1; i++) {
grid[0][i+1] += grid[0][i];
}
for (int i = 1; i < row; i++) {
for (int j = 1; j < col; j++) {
grid[i][j] += grid[i][j-1] > grid[i-1][j] ? grid[i-1][j] : grid[i][j-1];
}
}
return grid[row-1][col-1];
}
}
62_Unique_Paths
Simpler DP...
public class Solution {
public int uniquePaths(int m, int n) {
if (m == 0 || n == 0) return 0;
int grid[][] = new int[m][n];
for (int i = 0; i < m; i++) {
grid[i][0] = 1;
}
for (int i = 1; i < n; i++) {
grid[0][i] = 1;
}
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
grid[i][j] = grid[i][j-1] + grid[i-1][j];
}
}
return grid[m-1][n-1];
}
}
174_Dungeon_Game
Elegant DP solution: create a healthGrid to store the least health needed, dp from finish point to start point, with Transition Format Dp[i][j] = max(1,min(dp[i+1][j],dp[i][j+1]) - grid[i][j]). It's also possible to dp on the original dungeon array, but I am too lazy to spare the effort. :(
public class Solution {
public int calculateMinimumHP(int[][] dungeon) {
int row = dungeon.length;
int col = dungeon[0].length;
int healthGrid[][] = new int [row][col];
healthGrid[row - 1][col - 1] = Math.max(1, 1 - dungeon[row - 1][col - 1]);
for (int i = row - 2; i >= 0; i--) {
healthGrid[i][col - 1] = Math.max(1, healthGrid[i + 1][col - 1] - dungeon[i][col - 1]);
}
for (int i = col - 2; i >= 0; i--) {
healthGrid[row - 1][i] = Math.max(1, healthGrid[row - 1][i + 1] - dungeon[row - 1][i]);
}
for (int i = row - 2; i >= 0; i--) {
for (int j = col - 2; j >= 0; j--) {
healthGrid[i][j] = Math.max(1, Math.min(healthGrid[i + 1][j], healthGrid[i][j + 1]) - dungeon[i][j]);
}
}
return healthGrid[0][0];
}
}