Kotlin中take、drop方法使用
2022-05-31 本文已影响0人
因为我的心
1、 take方法:
private fun take() {
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
//take函数是根据传入的参数挑出该集合【前n个元素】的子集合
val mNewList1 = mList.take(2)
println(mNewList1)
//[1, 2]
//takeLast函数是根据传入的参数挑出该集合【倒数n个元素】的子集合
val mNewList2 = mList.takeLast(2)
println(mNewList2)
//[9, 0]
}
2、 takeWhile
private fun takeWhile() {
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
//takeWhile : 从头开始取值,不符合立即停止
val mNewList3 = mList.takeWhile {
it % 2 == 0
}
println(mNewList3)
//[]
//takeLastWhile : 从尾开始取值,不符合立即停止
val mNewList4 = mList.takeLastWhile {
it % 2 == 0
}
println(mNewList4)
//[0]
}
3、 takeIf
private fun takeIf() {
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
//如果符合返回它
val mNewList5 = mList.takeIf {
it.size == 10 //true
}
println(mNewList5)
//[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
val mNewList51 = mList.takeIf {
it.size == 5 //false
}
println(mNewList51)
//null
}
4、 takeUnless
private fun takeUnless() {
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
//如果不符合返回它
val mNewList6 = mList.takeUnless {
it.size == 10 //true
}
println(mNewList6)
//null
val mNewList61 = mList.takeUnless {
it.size == 5 //false
}
println(mNewList61)
//[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
}
5、 drop
private fun drop() {
//去掉前n个开始取值
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
val resultList = mList.drop(3)
println(resultList)
}
//[4, 5, 6, 7, 8, 9, 0]
6、 dropLast
private fun dropLast() {
//去掉最后n个开始取值
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
val resultList = mList.dropLast(3)
println(resultList)
}
//[1, 2, 3, 4, 5, 6, 7]
7、dropLastWhile
private fun dropWhile() {
//从头开始找不满足的开始取值,满足的抛弃头部
val mList = mutableListOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 0)
val resultList = mList.dropWhile { it <= 1 }
println(resultList)
}
//[2, 3, 4, 5, 6, 7, 8, 9, 0]
链接:https://blog.csdn.net/sinat_31057219/article/details/105996133